x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation
and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)

Now, factoring the term:

The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation,
the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,


So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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Answer:
Step 2
Step-by-step explanation:
Michelle's step in trying to solve the equation is given below:

Michelle made a mistake in Step 2.
The right hand side of Step 1: 
Rather, the correct sum is:

Correct answers in reasoning and statements together.
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Answer:
1/2
((-2)^2-(4*2)^1/3)/abs(-2*2)
-2^2 = 4
4*2 = 8
-2*2 = -4 and abs of that is 4
4-(8)^1/3/4
8^1/3 = 2
4-2 = 2
2/4 = 1/2
Step-by-step explanation: