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castortr0y [4]
2 years ago
7

Find the volume of a cube whose surface area is 150 ft2?

Mathematics
2 answers:
s344n2d4d5 [400]2 years ago
8 0

Hey ! there

Answer:

  • Volume of cube is <u>1</u><u>2</u><u>5</u><u> </u><u>ft³</u><u> </u><u>.</u>

Step-by-step explanation:

In this question we are given with <u>surface </u><u>area </u><u>of </u><u>cube </u><u>that </u><u>is </u><u>1</u><u>5</u><u>0</u><u> </u><u>ft²</u><u> </u><u>.</u> And we're asked to find the <u>volume</u><u> of</u><u> cube</u><u> </u><u>.</u>

For finding volume of cube, we need to find the edge of the cube and formula for finding surface area of cube i.e. ,

\quad \quad   \underline{\boxed{\frak{Surface \:  Area_{(Cube)}  = 6(edge) {}^{2} }}}

<u>Solution</u><u> </u><u>:</u><u> </u><u>-</u>

As in the question it is given that surface area of cube is 150 . So ,

\quad \: \hookrightarrow \qquad \:  \sf{150 = 6(edge) {}^{2} }

Dividing with 6 on both sides :

\quad \: \hookrightarrow \qquad \:  \sf{  \cancel{\dfrac{150}{6} } =  \dfrac{ \cancel{6}(edge) {}^{2}}{ \cancel{6} } }

Simplifying it ,

\quad \: \hookrightarrow \qquad \:  \sf{ (edge) {}^{2}  = 25}

Now for removing square , taking square root to both sides :

\quad \: \hookrightarrow \qquad \:  \sf{   \sqrt{(edge) {}^{2} }  =  \sqrt{25}}

We get ,

\quad \: \hookrightarrow \qquad \:    \underline{\boxed{\sf{ edge = 5 \: ft}}}

  • <u>Therefore</u><u> </u><u>,</u><u> </u><u>edge </u><u>of </u><u>cube </u><u>is </u><u>5</u><u> </u><u>ft </u><u>.</u>

As we know the edge of cube , so we can easily find the volume of cube . We know that ,

\quad \qquad \:    \underline{\boxed{\frak{Volume_{(Cube)} = (edge) {}^{3} }}}

Now ,

\quad \longmapsto \qquad \: (5) {}^{3}

We get ,

\quad \longmapsto \qquad \:    \green{\underline{\boxed{\frak{125 \: ft {}^{3} }}}} \quad \bigstar

  • <u>Henceforth</u><u> </u><u>,</u><u> </u><u>volume</u><u> of</u><u> cube</u><u> is</u><u> </u><u>1</u><u>2</u><u>5</u><u> </u><u>ft³</u><u> </u><u>.</u>

<h2><u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>
Brrunno [24]2 years ago
7 0

Given:

  • Surface area of cube = 150 ft²

To Find:

  • Volume of cube

Solution:

As here in Question we are given Surface area of cube is 150 sq. feet. So, firstly we have find the side of edge of cube. Let 'a' be the edge of the cube

We know that,

\: \: \: \: \dashrightarrow \sf \: \: \: \: Surface  \: area_{(Cube)} = 6a^2  \\  \\

Substituting the required values,

\: \: \: \: \dashrightarrow \sf \: \: \: \: 150 = 6a^2  \\  \\ \: \: \: \: \dashrightarrow \sf \: \: \: \:   \frac{150}{6}   =  {a}^{2}  \\  \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: 25 =  {a}^{2}  \\  \\ \: \: \: \: \dashrightarrow \sf \: \: \: \:  \sqrt{25}  = a \\  \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: { \underline{ \boxed{ \sf{ \pink{5 = a}}}} } \\  \\

  • Edge of the cube is 5 feet

Now,

\: \: \: \: \dashrightarrow \sf \: \: \: \: Volume = (edge)^3 \\  \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: Volume = (5)^3 \\  \\ \: \: \: \:\dashrightarrow \sf \: \: \: \: {\underline{\boxed{\sf{\pink{Volume =125 \: {ft}^{3}}}}}}  \\  \\

Hence,

  • Volume of the cube is 125 cu. feet
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Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

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Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, \frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}  the denominator becomes zero i.e

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which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2  in the equation,

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So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/2456302

#learnwithBrainly

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Step-by-step explanation:

Michelle's step in trying to solve the equation is given below:

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Rather, the correct sum is:

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