Let 4x = the girth (each side = x) Let y = the length
4x + y = 114 maximum y = 114 - 4x
volume = x^2 * y v = x^2 * (114 - 4x) v = 114x^2 - 4x^3 . . . . . . v is maximum (or minimum) when it's derivative = 0 v ' = 228x - 12x^2
228x - 12x^2 = 0 12x * (19 - x) = 0
x = 0 <=== this is obviously a minimum volume or x = 19 inches <=== for maximum volume
4x + y = 1144*19 + y = 114y = 38 <===
The largest volume is 19 x 19 x 38
Answer:
<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).</em>
<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒</em>
<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number) </em>
<em>The events are independent (the outcome of flipping thee coin has no effect on the outcome of rolling the die).⇒ P(head and an even number) = P(head) ×</em><em> P(even number)</em>
<em> P(even number)Assuming a fair coin and a fair die:</em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) </em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%</em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) </em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50%</em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).</em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number) </em>
<em> P(even number)Assuming a fair coin and a fair die:P(head) =50%P(even number) =50% (since half the numbers on a die are even).P(head and even number) =50%×50%</em><em>=25%</em>
Answer:
x=18-/2 =9-5=1.929
Step-by-step explanation:
The answer is 10,140,000fett because 10.14(the length of each car) times 1,000,000 is 10,140,000