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kherson [118]
3 years ago
15

Someone help me with these math problems please !! (It is not obligatory to put the explanation so I save time and you will answ

er me more quickly please!

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

\frac{2}{3} * 5 = \frac{2}{3}\frac{3}{2} x  \\

x = 10/3

You might be interested in
1²+3²+4²+.......+(2n-2)²= ⅓n(2n-1)(2n+1)
sergiy2304 [10]
                       1² + 3² + 4² + 4(n - 1)² = ¹/₃n(2n - 1)(2n + 1)
                       1² + 3² + 4² + (2n - 2)² = ¹/₃n(2n - 1)(2n + 1)
              1 + 9 + 16 + (2n - 2)(2n - 2) = ¹/₃n(2n(2n + 1) - 1(2n + 1))
  10 + 16 + (2n(2n - 2) - 2(2n - 2)) = ¹/₃n(2n(2n) + 2n(1) - 1(2n) - 1(1)    16 + (2n(2n) - 2n(2) - 2(2n) + 2(2)) = ¹/₃n(4n² + 2n - 2n - 1)
                     26 + (4n² - 4n - 4n + 4) = ¹/₃n(4n² - 1)
                            26 + (4n² - 8n + 4) = ¹/₃n(4n² - 1)
                              26 + 4n² - 8n + 4 = ¹/₃n(4n²) - ¹/₃n(1)
                              4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
                                    4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
                                          + ¹/₃n                     + ¹/₃n
                                 4n² - 7²/₃n + 30 = 1¹/₃n³
                   -1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
             -3(-1¹/₃n³ + 4n² - 7²/₃n + 30) = -3(0)
-3(-1¹/₃n³) - 3(4n²) - 3(-7²/₃n) - 3(30) = 0
                        4n³ - 12n² + 23n - 90 = 0
8 0
4 years ago
Some one explain this to me
lubasha [3.4K]
7.50
25% also equals 1/4 so divide 130.00 by 4 which equals 32.50
subtract 32.50 from 130.00 which equals the cost, 97.50
97.50 minus 90$ is 7.50, therefore that is the answer
4 0
3 years ago
Helppppppp pleaseeeeeeee
Lilit [14]
B. Is the right answer

First you have to take the common elements then use an identity/formula to get the rest

x^3 - 3x^2 + x-3
x^2 (x-3) +1 (x-3)
(x^2 +1) (x-3)
(x-1)(x+1)(x-3) {using a^2-b^2 on x^2-1^2}
4 0
3 years ago
Which statements are true about x? Select three options
polet [3.4K]

The true statements about x are:

x ∈ B ∪ C

x ∈ B ∩ C

x ∈ A ∪ C

<h3>Further explanation</h3>

A set is a clearly defined collection of objects.

To declare a set can be done in various ways such as:

  • With words or the nature of membership
  • With set notation
  • By registering its members
  • With Venn diagrams

Multiplying set A x B is by pairing each member of set A with each member of set B.

<u>Example: </u>

<em>A = {1, 2, 3} </em>

<em>B = {a, b} </em>

Then

A x B = {(1, a), (1, b), (2, a), (2, b), (3, a), (3, b)}

Union of set A and B ( A ∪ B ) is rewriting each member A and combined with each member B.

Intersection of set A and B ( A ∩ B ) is to find the members that are both in Set A and Set B.

<u>Example: </u>

<em>A = {1, 2, 3, 4} </em>

<em>B = {3, 4, 5} </em>

A ∪ B = {1, 2, 3, 4, 5}

A ∩ B = {3, 4}

Let us now tackle the problem!

To solve this problem, it is better to draw the Venn diagram as shown in the picture in the attachment.

Let :

A = { p , q , s , t }

B = { q , r , t , x }

C = { s , t , v , x }

\texttt{ }

B \cup C = \{ r , q , t , v , \boxed{x} \} ✔

B \cap C = \{ t  , \boxed{x} \} ✔

A \cup C = \{ p , q , s , t , v , \boxed{x} \} ✔

A \cap C = \{ s , t \} ⤬

A = \{ p , q , s , t \} ⤬

\texttt{ }

From the results above, it can be concluded that the correct statements are:

x ∈ B ∪ C

x ∈ B ∩ C

x ∈ A ∪ C

\texttt{ }

<h3>Learn more</h3>
  • Mean , Median and Mode : brainly.com/question/2689808
  • Centers and Variability : brainly.com/question/3792854
  • Subsets of Set : brainly.com/question/2000547

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Sets

Keywords: Sets , Venn , Diagram , Intersection , Union , Mean , Median , Mode

5 0
3 years ago
Read 2 more answers
Consider a circle whose equation is x + y - 2x - 8=0. Which statements are true? Select three options
Mandarinka [93]

Answer:

The standard form of the equation is

{(x   -  1)}^{2}  +  {(y - 0)}^{2} =  {3}^{2}

Step-by-step explanation:

The given circle has equation:

{x}^{2}  +  {y}^{2}  - 2x - 8 = 0

We regroup similar terms to obtain:

{x}^{2} -2x +  {y}^{2}  = 8

We now complete the square to obtain:

{x}^{2} -2x +  {( - 1)}^{2} +  {y}^{2}  = 8 +  {( - 1)}^{2}

{(x   -  1)}^{2}  +  {(y - 0)}^{2} = 9

Or

{(x - 1)}^{2}  +  {(y - 0)}^{2} =  {3}^{2}

This is now of the form:

{(x   -  h)}^{2}  +  {(y - k)}^{2} =  {r}^{2}

which is referred to as the standard form equation of the circle:

4 0
4 years ago
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