What is the interquartile range of the data set below? Growth in feet of oak trees: 68,80,73,90,120,94,76,112,101,94,72 (1) 22
sdas [7]
<span>68,80,73,90,120,94,76,112,101,94,72 --->
68, 72, 73, 76, 80, 90, 94, 94, 101, 112, 120
Median = 90
Lower Median = 73
Upper Median = 101
IQR = 101 - 73
IQR = 28</span>
Answer:
14
Step-by-step explanation:
<h2><u>Solve for x</u></h2>
<u />
this can be solved by square rooting 196

x = 14
<h3><u>the value for x is 14</u></h3>
1/2 because when you divide by 1/2 you get 1/6 , if you do the problem backwards you get 1/6