Answer:
5 units
Step-by-step explanation:
±√(- 2 - 1)^2 + (- 1 - 3)^2 = ±5 (rej - 5 since distance > 0)
Apply distance formula
This is a topic on coordinate geometry. If you would like to find out more you can give my Instagram page a follow as I'll be updating on this topic soon. In addition, I will be posting other useful materials created by myself at the same platform too!
Answer:
x-2
Step-by-step explanation:
<h3>
Answer: 1</h3>
========================================================
Explanation:
We're given the height in relation to base BC, so we need to find the length of this base. This is the same as finding the distance from B to C.
Turn to the distance formula

Coincidentally, the base and height are the same. This won't always be the case.
Now we can find the area of the triangle

The area of the triangle is 1 square unit.
See diagram below.
Answer:
The first picture's answer would be (6, 21)
Step-by-step explanation:
You have to find the points on the 8th and the 9th day, and then you would add them together, and then divide by two finding the average, which would be 24 and 18, so when added, you get 42, divided by 2 you get 21. You look on the graph for the point with 21, and you find it is on 6.
Hi there!
»»————- ★ ————-««
I believe your answer is:
»»————- ★ ————-««
Here’s why:
- Recall the Triangle Angle Sum Theorem: The three angles of all triangles add up to a sum of 180°.
- We will set up an equation based on this and then solve.
⸻⸻⸻⸻

⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.