Question

According to the general equation for conditional probability, if P(A^B)=4/7 and P(B)=7/8, what is P(A B)?

Answer 1

D.32/49 is your correct answer

Answer 2

Answer: P(A|B)=$\dfrac{32}{49}$

Step-by-step explanation:

Since we have given that

P(A∩B)= $\dfrac{4}{7}$

and P(B) = $\dfrac{7}{8}$

We need to find P(A|B).

As we know the formula for "Conditional Probability ":

$P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}\\\\P(A\mid B)=\dfrac{\dfrac{4}{7}}{\dfrac{7}{8}}\\\\P(A\mid B)=\dfrac{4\times 8}{7\times 7}\\\\P(A\mid B)=\dfrac{32}{49}$

Hence, P(A|B) = $\dfrac{32}{49}$