5x y>_10 x y<_6 x 4y>_12 x>_0 y>_0 minimum for c=10,000x + 20,000y
1 answer:
We are given inequalities : 5x+y=>10
x+y<=6
x+4y=>12
x=>0
y=>0 .
Let us graph it first and the find the coordinate of the vertices of feasible region.
Coordinates of the feasible region are (1,5) , (1.474, 2.632) and (4,2).
Now, we need to plug those cordinates (1,5) , (1.474, 2.632) and (4,2) in the given function c=10,000x + 20,000y.
Let us plug those points one by one.
For (1,5)
c=10,000x + 20,000y = 10,000(1)+ 20,000(5)= 10,000+ 100,000 = 110,000.
For (1.474, 2.632)
C = 10,000(1.474)+ 20,000(2.632) = 67,380.
For (4,2)
C = 10,000(4)+ 20,000(2) = 80,000.
We got the minimum value 67,380 for (1.474, 2.632) coordinate.
Therefore, minimum for given function C=10,000x + 20,000y is 67,380.
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<u>Answer</u>:
18 clips for $7.38 is the best value deal.
<u>Step-by-step explanation:</u>
An office is restocking office supplies. The table below shows the cost for the number of boxes of paperclips. We need to find what is the best value is.
To find the best value for money we can check the price of each paperclip.
To check the price of each paper clip we can use the following formula:
Now we can calculate the best value deal as follows:
So, from looking at the prices of each paperclip we can conclude that the 18 clips for $7.38 is the best value deal.
