What are the solutions to the system of equations graphed below?

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Answer:

(0,-4) and (2,0)

Step-by-step explanation:

you cut off the screen shot, so not all answer options are visible.

but from the graph we can pretty reliably deduct, that the solutions (the crossing points of both functions) are

(0,-4) and (2,0)

You might be interested in

If $(2x+5)(x-3)=14$, find the sum of the possible values of $x$.

MA_775_DIABLO [31]

Answer:

x = 1/4 ± 1/4√233

Step-by-step explanation:

(2x + 5)(x - 3) = 14

~Use FOIL on the left side

2x² - 6x + 5x - 15 = 14

~Combine like terms

2x² - x - 15 = 14

~Subtract 14 to both sides

2x² - x - 29 = 0

~Use the quadratic formula and simplify

x = 1/4 ± 1/4√233

Best of Luck!

7 0

3 years ago

Jill has a collection of bugs. Her collection contains butterflies and tarantulas. She has 47 bugs and counts 320 total legs. (N

prisoha [69]

Answer:

The solution to this system of equations is:

B = 28
T = 19

Step-by-step explanation:

We are given that Jill has 47 bugs and counts a total 320 legs.

We can concur that by adding the total number of butterflies and the total number of tarantulas, we will get 47 bugs.

$\text{tarantulas + butterflies} = 47$

We are also told that T is tarantulas and B is butterflies.

$T + B = 47$

Then, we also know that butterflies have 6 legs and tarantulas have 8 legs. So, for every tarantula, we get a multiple of 8 and for butterflies, we get a multiple of 6. This gives us a new equation:

$6B + 8T = 320$

Now, we can set up a system of equation.

$\displaystyle \left \{ {{B + T = 47} \atop {6B + 8T = 320}} \right.$

Using the first equation, we can solve for B.

$\displaystyle B + T = 47\\\\B + T - T = 47 - T\\\\B = 47 - T$

Then, we can substitute this value of B into the second equation and solve for T.

$\displaystyle 6(47-T)+8T=320\\\\282 - 6T + 8T = 320\\\\282 + 2T = 320\\\\2T + 282 = 320\\\\2T + 282 - 282 = 320 -282\\\\2T = 38\\\\\frac{2T}{2}=\frac{38}{2}\\\\T = 19$