Answer:
Your answer would be 5400.
Step-by-step explanation:
You have to follow PEMDAS for this one. You will start within the parenthesis and add 10 and 20 together to get 30. You would then times that by 20 and get 600. Finally, you would mulitply that by 9 and get 5400 as your answer..
The amount of shampoo required by Morgan each week to bathe her dog = 2 oz
So
The amount of shampoo required by Morgan in 7 days to bathe her dog = 2 oz
The amount of shampoo remaining after 4 weeks = 34 oz
So the amount of shampoo remaining after (4 * 7) days = 34 oz
The amount of shampoo remaining after 28 days = 34 oz
The amount of shampoo that Morgan uses in 28 days = (2/7) * 28 oz
= 2 * 4 oz
= 8 oz
Then
8 oz of shampoo is required by Morgan in = 28 days
Then
34 oz of shampoo will be used in = (28/8) * 34 days
= 7 * 17 days
= 119 days
So
The total number of
days before the bottle becomes empty = 119 + 8 oz
= 127 days
Answer: 1 1/4feet
Step-by-step explanation:
From the question, we are informed that the depth of the water in the pool changes by −3/4 foot every hour and that the depth of the water was 5 feet when she started draining.
The depth of the water after 5 hours will be:
= 5 - 3/4(5)
= 5 - 15/4
= 5 - 3 3/4
= 1 1/4 feet
Answer: 1.509
Step-by-step explanation:
The formula of Margin of Error for (n<30):-

Given : Sample size : n= 22
Level of confidence = 0.99
Significance level : 
Using the t-distribution table ,
Critical value : 
Standard deviation: 
Then, we have

Hence, the margin of error for a 99% confidence interval for the population mean =1.509