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AlekseyPX
3 years ago
13

What is 500+222+221 and

Mathematics
2 answers:
VMariaS [17]3 years ago
7 0

Answer:

Step-by-step explanation:

500+222+221 = 943

Gnesinka [82]3 years ago
7 0

Answer:

943

Hope that this helps!

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Simplify (tan(θ)+cot(θ))/(sec(θ)•csc(θ)) completely
AlekseyPX
\dfrac{\tan\theta+\cot\theta}{\sec\theta\csc\theta}=\dfrac{\dfrac{\sin\theta}{\cos\theta}+\dfrac{\cos\theta}{\sin\theta}}{\dfrac1{\cos\theta}\dfrac1{\sin\theta}}=\dfrac{\sin^2\theta+\cos^2\theta}1=1
6 0
3 years ago
The mayor of a town places a map of the town on a coordinate grid with Town Hall at the point (0,0) and with each unit represent
Lorico [155]

Answer:

Given that the question rightly asks the amount it cost to drive from Smithville to Jones City, we have;

The question rightly asks the amount it cost to drive from Smithville to Jones City is approximately $7.209

Step-by-step explanation:

The coordinates of Smithville is (-25, 10)

The coordinates of Jones City is (15, 12)

The cost of driving a car for a mile = $0.18

Therefore, the distance from Smithville to Jones City is given by the formula for the distance, l, between two points with coordinates as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Where;

(x₁, y₁) = (-25, 10) and (x₂, y₂) = (15, 12)

l = \sqrt{\left (12-10  \right )^{2}+\left (15-(-25)  \right )^{2}} = 2 \cdot \sqrt{401}

The distance from Smithville to Jones City = 2·√401 ≈ 40.05 miles

The amount, A, it cost to drive from Smithville to Jones City a distance of approximately 40.05 miles is therefore given as follows;

A = 40.05 miles × $0.18 ≈ $7.209

8 0
3 years ago
Look at the formula for finding distance. Which of the following is the formula to find time? [picture included] ​
Lelu [443]

Answer:

A.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Pls tell the answer for 50 points!
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Answer:

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Explanation:

(the photo)

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Answer:

36

Step-by-step explanation:

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