Question

Simplify (tan(θ)+cot(θ))/(sec(θ)•csc(θ)) completely

Answer 1

$\dfrac{\tan\theta+\cot\theta}{\sec\theta\csc\theta}=\dfrac{\dfrac{\sin\theta}{\cos\theta}+\dfrac{\cos\theta}{\sin\theta}}{\dfrac1{\cos\theta}\dfrac1{\sin\theta}}=\dfrac{\sin^2\theta+\cos^2\theta}1=1$