Simplify (tan(θ)+cot(θ))/(sec(θ)•csc(θ)) completely

1 answer:

6 0

$\dfrac{\tan\theta+\cot\theta}{\sec\theta\csc\theta}=\dfrac{\dfrac{\sin\theta}{\cos\theta}+\dfrac{\cos\theta}{\sin\theta}}{\dfrac1{\cos\theta}\dfrac1{\sin\theta}}=\dfrac{\sin^2\theta+\cos^2\theta}1=1$

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