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Anarel [89]
3 years ago
10

(4x 10) + (5x2) + (7 x 1 10) + (8 160) = ?

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

It's 45.78

Step-by-step explanation:

4 x 10 = 40

5 x 1 = 5

7 x 1/10 = 0.7

8 x 1/100 = 0.08

add them all together and you get 45.78

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Solve the exponential equation: 4x – 2 = 1∕4
barxatty [35]

Answer:

9/16

Step-by-step explanation:

4x-2= 1/4

collect like terms

4x= 1/4+2

using the basic knowledge of lcm 1/4 +2 is 9/4

then 4x is equal to 9/4

therefore x is equal to 9/16

8 0
2 years ago
Read 2 more answers
I need help again sorry
RideAnS [48]

Answer:

I want say it is C just by how close in proximity it is to E

Step-by-step explanation:

3 0
3 years ago
Hospitals typically require backup generators to provide electricity in the event of a power outage. Assume that emergency backu
JulsSmile [24]

Answer:

a) There is a 10.24% probability that both generators fail during a power outage.

b) There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

Step-by-step explanation:

For each emergency backup generator, there are only two possible outcomes. Either they work correctly, or they fail. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

Assume that emergency backup generators fail 32% of the times when they are needed. So they work correctly 100-32 = 68% of the time. So p = 0.68

There are two generators, so n = 2

a. Find the probability that both generators fail during a power outage

This is P(X = 0)

So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.68)^{0}.(0.32)^{2} = 0.1024

There is a 10.24% probability that both generators fail during a power outage.

b. Find the probability of having a working generator in the event of a power outage. Is that probability high enough for the hospital? Assume the hospital needs both generators to fail less than 1% of the time when needed.

Either there are no working generators, or there is at least one working generator. The sum of the probabilities of these events is decimal 1. So

P(X = 0) + P(X \geq 1) = 1

We want P(X \geq 1). So

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1024 = 0.8976

There is an 89.76% probability of having a working generator in the event of a power outage, which is not high enough for the hospital.

To be high enough for the hospital, this probability should be at least of 99%.

7 0
4 years ago
Target sells a watch for $99 and offers a 15% discount. Walmart sells the same watch for $59 and offers a 10% discount. Which st
joja [24]

Answer:

Walmart

Step-by-step explanation:

Target:  15% of 99 = $14.85      If you reduce $99 by $14.85 you get $84.15

Walmart:  10% of 59 = $5.90     If you reduce $59 by $5.90 you get $53.10

5 0
3 years ago
Please help me I'm having problems with this question and I don't know what it is if you do answer this question I really apprec
slamgirl [31]
I think it is A and B
7 0
3 years ago
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