(5x – 3y) (3x + 4y)

Mathematics

2 answers:

MariettaO [177]3 years ago

6 0

Answer:

$\boxed{\red{15 {x}^{2} + 11xy - 12 {y}^{2}}}$

Step-by-step explanation:

$\blue{(5x - 3y)(3x + 4y)} \\ \blue{5x(3x + 4y) - 3y(3x + 4y)} \\ \blue{15 {x}^{2} + 20xy - 9xy - 12 {y}^{2} } \\ \pink{= 15 {x}^{2} + 11xy - 12 {y}^{2} }$

ycow [4]3 years ago

5 0

Answer:

Solution,

( 5x - 3y) ( 3x +4y)

Multiply each terms in the first parentheses by each term in the second paranthesis.

5x * 3x + 5x * 4y - 3y * 3x - 3y * 4y

Calculate the product

15x^2 + 20xy -9xy -12y^2

Collect like terms and simplify

15x^2 + 11xy -12y^2

Hope this helps...

Good luck on your assignment...

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Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of

bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

= $\frac{7}{100}$

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = $1-\frac{7}{100}$

⇒ prob = $\frac{93}{100}$

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = $(\frac{93}{100})^{12}$