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Svetllana [295]
3 years ago
7

(5x – 3y) (3x + 4y)​

Mathematics
2 answers:
MariettaO [177]3 years ago
6 0

Answer:

\boxed{\red{15 {x}^{2}  + 11xy - 12 {y}^{2}}}

Step-by-step explanation:

\blue{(5x - 3y)(3x + 4y)} \\ \blue{5x(3x + 4y) - 3y(3x + 4y)} \\ \blue{15 {x}^{2}  + 20xy - 9xy - 12 {y}^{2} } \\ \pink{=  15 {x}^{2}  + 11xy - 12 {y}^{2} }

ycow [4]3 years ago
5 0

Answer:

<h2>15 {x}^{2}  + 11xy - 12 {y}^{2}</h2>

Solution,

( 5x - 3y) ( 3x +4y)

Multiply each terms in the first parentheses by each term in the second paranthesis.

5x * 3x + 5x * 4y - 3y * 3x - 3y * 4y

Calculate the product

15x^2 + 20xy -9xy -12y^2

Collect like terms and simplify

15x^2 + 11xy -12y^2

Hope this helps...

Good luck on your assignment...

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Answer: 8 left over

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Natalka [10]
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Given the box plot, will the mean or the median provide a better description of the center? box plot with min at 11, Q1 at 22. 5
Slav-nsk [51]

The median, because the data distribution is skewed to the right.

Given that

The box plot with the following parameters:  

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Maximum value at 37.5.

According to the question

When a distribution has a longer tail to one of its sides, then it is said to be skewed.

Since the tail is longer to the left, it is said to be left-skewed.

The data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile  (22.5).

For skewed data, we always prefer the median because it is less affected by the outliers and if the mean is chosen, the value of the mean is biased towards the side that has larger values while the median does not get affected by it. So, we choose the median.

For skewed distributions, the median is the best measure of center.

Hence, the median, because the data distribution is skewed to the right.

To know more about Mean click the link given below.

brainly.com/question/2508120

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2 years ago
Phillip is mowing his backyard. His backyard is oddly shaped.
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= 14X + 6

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