Question

A teacher designs a test so a student who studies will pass94% of the time, but a student who does not studywill pass14% of the time. A certain student studies for91% of the tests taken. On a given test, what is theprobability that student passes

Answer 1

Answer:

0.868 = 86.8% probability that the student passes.

Step-by-step explanation:

Probability of the student passing:

94% of 91%(when the student studies for the test).

14% of 100 - 91 = 9%(when the student does not study for the test). So

$p = 0.94*0.91 + 0.14*0.09 = 0.868$

0.868 = 86.8% probability that the student passes.