Answer:
d. Approximate the standard normal distribution with the Student's t distribution
(0.2199 ; 0.2327)
Step-by-step explanation:
Given that :
Sample size, n = 31
Sample mean, xbar = 0.2258
Sample standard deviation, s = 0.0188
Confidence interval (C. I) :
xbar ± margin of error
Margin of Error : Tcritical * s/sqrt(n)
Degree of freedom, df = n - 1 = 31 - 1 = 30
Tcritical value :
T0.05/2, 30 = 2.042
Margin of Error = 2.042 * 0.0188/sqrt(31)
Margin of Error = 0.0068949
C. I = 0.2258 ± 0.0068949
Lower boundary : (0.2258 - 0.006895) = 0.2189
Upper boundary : (0.2258 - 0.006895) = 0.2327
(0.2199 ; 0.2327)
Answer:
Lin ran at 2.9 meters per second. She can run 174 meters in a minute (2.9 times 60)
Step-by-step explanation:
If she can run 2.9 meters in a second then when you times that by four you get how far she can run in a minute
Answer:
yedhxncj
Step-by-step explanation:
tgrfhhffbvxvxxnndhndhfdhduduriI'm playing with my pu**y find me here - www.nowdate.fun
Check the picture below.
now, bear in mind that, there are 60minutes in 1 degree, so 23' is just 23/60 degrees or about 0.38 degrees.
and 29' is just 29/60 degrees or about 0.48 degrees.
so 16°23' is about 16.38°, and 49°29' is about 49.48°
make sure your calculator is in Degree mode.
Answer:
10 cm
Step-by-step explanation:
Diameter= 2X radius
20/ 2 = radius
20/2 = 10 cm
