Please help

Sergio039 [100]

Answer:

The answer could be 0 or 1 out of 4, because choosing a card at first and not putting it back, then picking a second card at random, it would likely be one in zero attempts to pick 3 again but otherwise that it could be 1 out of 4 because it could be possible picking 3 at the first try.

3 0

3 years ago

HELP I WILL GIVE 50 POINTS AND BRAINLIEST TO WHOEVER ANSWERS FIRST Graph y>1−3x.

AleksandrR [38]

Answer:

The last graph

Step-by-step explanation:

This is because when there is a greater than sign, the line on the graph is dotted and the shaded area is facing upwards. I try to remember that when there is a greater than sign or a greater than or equal to sign, the shaded area faces up towards the sky.

Hope this helps. Please inform me if my answer is wrong.

7 0

3 years ago

Read 2 more answers

5 minus the product of 2 and a number is 7 as a equation

mrs_skeptik [129]

Answer:

$2x - 5 = 7$

Step-by-step explanation:

product is the result of multiplication which means multiplication is involved with 2 and a number which can be substituted for x

5 is subtracted from all of that

7 is the answer of it all

5 0

4 years ago

The function Ald) = 0.45d + 180 models the amount A, in dollars, that Terry's company pays him based on

Solnce55 [7]

Answer: Choice A) $0.45

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Explanation:

Plug in d = 0 and you'll have A(d) = 0.45d+180 turn into A(0) = 180. This says that Terry is paid $180 even if he doesnt travel a single mile.

Now plug in d = 1. You should get A(1) = 180.45 as the result.

Subtract the results: 180.45 - 180 = 0.45

He has earned 45 cents or 0.45 dollars for traveling one mile

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A shortcut is to notice that the slope of the line is 0.45

It might help to view A(d) = 0.45d+180 as y = 0.45x+180. We see that the equation is in slope intercept form y = mx+b

m = slope = 0.45 tells us how much additional dollars Terry earns for each additional mile traveled

b = 180 = y intercept = starting amount of money Terry is paid, this amount does not change based on how many miles he travels.

7 0

3 years ago

Find the imaginary part of\[(\cos12^\circ+i\sin12^\circ+\cos48^\circ+i\sin48^\circ)^6.\]

iren [92.7K]

Answer:

The imaginary part is 0

Step-by-step explanation:

The number given is:

$x=(\cos(12)+i\sin(12)+ \cos(48)+ i\sin(48))^6$

First, we can expand this power using the binomial theorem:

$(a+b)^k=\sum_{j=0}^{k}\binom{k}{j}a^{k-j}b^{j}$

After that, we can apply De Moivre's theorem to expand each summand: $(\cos(a)+i\sin(a))^k=\cos(ka)+i\sin(ka)$

The final step is to find the common factor of i in the last expansion. Now:

$x^6=((\cos(12)+i\sin(12))+(\cos(48)+ i\sin(48)))^6$

$=\binom{6}{0}(\cos(12)+i\sin(12))^6(\cos(48)+ i\sin(48))^0+\binom{6}{1}(\cos(12)+i\sin(12))^5(\cos(48)+ i\sin(48))^1+\binom{6}{2}(\cos(12)+i\sin(12))^4(\cos(48)+ i\sin(48))^2+\binom{6}{3}(\cos(12)+i\sin(12))^3(\cos(48)+ i\sin(48))^3+\binom{6}{4}(\cos(12)+i\sin(12))^2(\cos(48)+ i\sin(48))^4+\binom{6}{5}(\cos(12)+i\sin(12))^1(\cos(48)+ i\sin(48))^5+\binom{6}{6}(\cos(12)+i\sin(12))^0(\cos(48)+ i\sin(48))^6$

$=(\cos(72)+i\sin(72))+6(\cos(60)+i\sin(60))(\cos(48)+ i\sin(48))+15(\cos(48)+i\sin(48))(\cos(96)+ i\sin(96))+20(\cos(36)+i\sin(36))(\cos(144)+ i\sin(144))+15(\cos(24)+i\sin(24))(\cos(192)+ i\sin(192))+6(\cos(12)+i\sin(12))(\cos(240)+ i\sin(240))+(\cos(288)+ i\sin(288))$

The last part is to multiply these factors and extract the imaginary part. This computation gives:

$Re x^6=\cos 72+6cos 60\cos 48-6\sin 60\sin 48+15\cos 96\cos 48-15\sin 96\sin 48+20\cos 36\cos 144-20\sin 36\sin 144+15\cos 24\cos 192-15\sin 24\sin 192+6\cos 12\cos 240-6\sin 12\sin 240+\cos 288$

$Im x^6=\sin 72+6cos 60\sin 48+6\sin 60\cos 48+15\cos 96\sin 48+15\sin 96\cos 48+20\cos 36\sin 144+20\sin 36\cos 144+15\cos 24\sin 192+15\sin 24\cos 192+6\cos 12\sin 240+6\sin 12\cos 240+\sin 288$

(It is not necessary to do a lengthy computation: the summands of the imaginary part are the products sin(a)cos(b) and cos(a)sin(b) as they involve exactly one i factor)

A calculator simplifies the imaginary part Im(x⁶) to 0

4 0

3 years ago