If PQ bisects CX at point J, and if JX = 4y and CJ = y+9 find y
1 answer:
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The y values from:
1. ₋6
2. ₋3
3. 0
4. 3
Given the x values and y value as y = 3x
1. when x = ₋2 then y = 3x
y = 3(₋2)
y = ₋6
2. when x = ₋1 then y = 3x
y = 3(₋1)
y = ₋3
3. when x = 0 then y = 3x
y = 3(0)
y = 0
4. when x = 1 then y = 3x
y = 3(1)
y = 3
therefore we get the points as (₋2 , ₋6) (₋1 , ₋3) (0,0) (1 , 3).The graph is pltted and attached.
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