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2 years ago

11

A quantity with an initial value of 9700 grows continuously at a rate of 0.65% per hour. What is the value of the quantity after

2.75 days, to the nearest hundredth?

1 answer:

Llana [10]2 years ago

7 0

Answer:

.65% / hr = .0065 / hr

2.75 days * 24 hrs / day = 66 hrs

66 hrs * .0065 / hr = .429

So our amount will become

A = A0 ( 1 + .429) = 9700 * 1.429 = 13860

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The answer is 12.58 rounded up it would be 13 so the correct answer is A

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3 years ago

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Step-by-step explanation:

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3 years ago

Jane is 5 times older than her sister. In 3 years, Jane’s sister will be 1/4 her age. Find the ages now

Korolek [52]

The present age of Jane is 45 years old and present age of her sister is 9 years old

<em><u>Solution:</u></em>

Let the present age of Jane be "x"

Let the present age of her sister be "y"

<em><u>Jane is 5 times older than her sister</u></em>

present age of Jane = 5(present age of her sister)

x = 5y ---------- eqn 1

<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>

Age of sister after 3 years = 3 + y

Age of jane after 3 years = 3 + x

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$3 + y = \frac{1}{4}(3 + x)$

Substitute eqn 1 in above equation

$3 + y = \frac{1}{4}(3 + 5y)\\\\12 + 4y = 3 + 5y\\\\5y - 4y = 12 - 3\\\\y = 9$

Substitute y = 9 in eqn 1

x = 5(9)

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Thus present age of Jane is 45 years old and present age of her sister is 9 years old

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3 years ago

Suppose the sample space for a probability experiment has 8 elements. If elements from the sample are selected without replaceme

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Step-by-step explanation:

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