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3 years ago

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PLEASE ANSWER: Identify the percent change as an increase or a decrease. Then find the percent of change. Round to the nearest t

enth if necessary.
A) 5 cups to 8 cups

B) 150 lbs to 135 lbs

C) $14 to $10

D) 1/3 to 2/3

E)1/3 to 1/6

1 answer:

kupik [55]3 years ago

6 0

Hey I’ve done some working out, check out the image, I hope it’s right

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Really need help with this

IrinaVladis [17]

Answer:

36.89°

Step-by-step explanation:

tan x = 15/20=3/4

x = 36.89

5 0

2 years ago

Plz help with this math. Can't find the area of the triangular faces.

Zina [86]

First of all, you have to find the area of both triangles:
$\frac{bh}{2}$
$\frac{4*4}{2}$
Or just 16 because there are 2 of the same triangles.

Now you have to find the area of the 3 rectangles.

The two that are in the front are 4*3 (l*h) or 12*2 (because there are 2 congruent rectangles. The area of those rectangles is 24 square mm.

Now you find the area of the back rectangle:
5.7*3 = 17.1

Finally, you add all the found numbers to figure out the surface area.
17.1 + 16 + 24 = 57.1 square millimeters.

Hope this helped,
Loafly

4 0

3 years ago

Compute using long division: 1,234÷68

Kruka [31]

Answer:

Quotient = 18

Remainder = 10

Step-by-step explanation:

1234/68

=> 68 x 1 = 68

=> 123 - 68 = 55

=> Take the 4 down

=> 554/68

=> 68 x 8 = 544

=> 554 - 544 = 10

So, the quotient = 18.

Remainder = 10

4 0

3 years ago

Sloan [31]

the answer has to be C

4 0

3 years ago

Typing errors in a text are either nonword errors (as when "the" is typed as "teh") or word errors that result in a real but inc

nordsb [41]

Answer:

a) X is binomial with n = 10 and p = 0.3

Y is binomial with n = 10 and p = 0.7

b) The mean number of errors caught is 7.

The mean number of errors missed is 3.

c) The standard deviation of the number of errors caught is 1.4491.

The standard deviation of the number of errors missed is 1.4491.

Step-by-step explanation:

For each typing error, there are only two possible outcomes. Either it is caught, or it is not. The probability of a typing error being caught is independent of other errors. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

10 word errors.

This means that $n = 10$

(a) If X is the number of word errors missed, what is the distribution of X ?

Human proofreaders catch 70 % of word errors. This means that they miss 30% of errors.

So for X, p = 0.3.

The answer is:

X is binomial with n = 10 and p = 0.3.

If Y is the number of word errors caught, what is the distribution of Y ?

Human proofreaders catch 70 % of word errors.

So for Y, p = 0.7.

The answer is:

Y is binomial with n = 10 and p = 0.7

(b) What is the mean number of errors caught?

$E(Y) = np = 10*0.7 = 7$

The mean number of errors caught is 7.

What is the mean number of errors missed?

$E(X) = np = 10*0.3 = 3$

The mean number of errors missed is 3.

(c) What is the standard deviation of the number of errors caught?

$\sqrt{V(Y)} = \sqrt{np(1-p)} = \sqrt{10*0.7*0.3} = 1.4491$

The standard deviation of the number of errors caught is 1.4491.

What is the standard deviation of the number of errors missed?

$\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.3*0.7} = 1.4491$

The standard deviation of the number of errors missed is 1.4491.

6 0

3 years ago