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3 years ago

10 POINTS (t−2)(t2−5t+1)

Mathematics

2 answers:

padilas [110]3 years ago

8 0

Answer:

$t^3-7t^2+11t-2$

Step-by-step explanation:

Liula [17]3 years ago

3 0

(t - 2 ) (t^2-5t + 1 )

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The number of cars sold weekly by a new automobile dealership grows according to a linear growth model. The first week the deale

marusya05 [52]

The number of cars that sold on the third week is (P3=26)

The number of cars that sold on the first week is (P4=33)

Step-by-step explanation:

Given:

The number of cars that sold on the first week is (P0=7)

The number of cars that sold on the second week is (P0=12)

We have to find the number of cars being sold on the upcoming week

From the data given above, frame the equation

Pn = Pn −1+7 ( 12-5=7 it denotes the cars sold in the first and the second week)

Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)

(If n=3)

Pn=5+7(3)

Pn=26

The number of cars that sold on the third week is (P3=26)

(If n=4)

Pn=5+7(4)

Pn=33

The number of cars that sold on the first week is (P4=33)

5 0

3 years ago

(Multiple Choice, 20 pts)

ivanzaharov [21]

Answer:

x = -3, x = 0 is a extraneous solution

Step-by-step explanation:

Step 1: Cross-multiply

3x² = 4x² + 3x

Step 2: Isolate x's

0 = x² + 3x

Step 3: Factor

0 = x(x + 3)

Step 4: Find roots

x = 0, -3

Step 5: Double check work

Plug in both to see if they both work. Only x = 0 should be extraneous. We now have our answer!

3 0

3 years ago

Which are not changed after a rotation

sineoko [7]

Where are your choices

5 0

3 years ago

Thandi deposits 850 into a bank. the bank will pay a simple interest rate of 8% per year. how much money will Thandi get when sh

marusya05 [52]

Answer:

1084.83932813 which you would round to 1085

4 0

2 years ago

A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa

Crank

Answer:

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

Step-by-step explanation:

Step(i):-

Given mean of the Population 'μ'= 25c.m

Given standard deviation of the Population 'σ' = 8c.m

Given sample size 'n' = 256

Let X₁ = 24

$Z_{1} = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } = -2$

Let X₂ = 25

$Z_{2} = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0$

Step(ii):-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)

= P( Z≤0) - P(Z≤-2)

= 0.5 + A(0) - (0.5- A(-2))

= A(0) + A(2) ( ∵A(-2) =A(2)

= 0.000+ 0.4772

= 0.4772

Final answer:-

The probability that the mean of my sample will be between 24 and 25 cm

P(24 ≤X⁻≤25) = 0.4772

4 0

3 years ago