Answer:
The seventh root of a^5
Step-by-step explanation:
is equal to
![\sqrt[7]{a^5}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Ba%5E5%7D)
because
![b^{1/m} = \sqrt[m]{b}](https://tex.z-dn.net/?f=b%5E%7B1%2Fm%7D%20%3D%20%5Csqrt%5Bm%5D%7Bb%7D)
hope this makes sense and helps
Ok so in order to do this, you have to set up an equation. Let's make a=the score of the first test and b=the score of the second test. (You can choose different variables, it doesn't matter.) It says the sum of the two equals 170. So, a+b=170. It also says that the score of the first was 6 less than the second. This can be shown as a=b-6. Now you can plug this in for a in your original equation. It will look like:
(b-6)+b=170
You can solve for b.
2b-6=170
2b=176
b=88
Since you want a, plug into either equation for b. I'll use the second one.
a=88-6
So, a=82
When I was A little ahead when I wanted berries and cream mommy made me do the Little lad dance but now mummy is gone
Answer:
c
Step-by-step explanation:
-3,2
thats the answer your welcome
