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Dima020 [189]
2 years ago
9

−4x + 3y =7 5x − 2y =35 What is the solution?

Mathematics
2 answers:
Rus_ich [418]2 years ago
6 0

Answer:

(17,25)

Step-by-step explanation:

To find the solution to the system, solve with elimination.

Equation 1.

−4x + 3y =7

Equation 2.

5x − 2y =35

To cancel out the y-variable, multiply the first equation by 2, and the second equation by 3.

2(−4x + 3y =7)

-8x+6y=14

3(5x − 2y =35)

15x-6y=105

Combine both equations.

-8x+6y=14

15x-6y=105

7x=119

x= 17

Plug in x into the first equation to solve for y.

-8x+6y=14

-8(17)+6y=14

-136+6y=14

6y=150

y=25

Bezzdna [24]2 years ago
4 0

Answer:   x = 39/10     y = 29/5

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Solve for a: a(a-3) =100
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Describe and correct the error(s) made in each of the problems below.
ladessa [460]

Answer:

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

Step-by-step explanation:

<u>Errors in Algebraic Operations </u>

It's usual that students make mistakes when misunderstanding the application of algebra's basic rules. Here we have two of them

  • When we change the signs of all the terms of a polynomial, the expression must be preceded by a negative sign
  • When multiplying negative and positive quantities, if the number of negatives is odd, the result is negative. If the number of negatives is even, the result is positive.
  • Not to confuse product of fractions with the sum of fractions. Rules are quite different

The first expression is

1-x / (5-x)(-x)=x-1 / x(x-5)

Let's arrange into format:

\displaystyle \frac{1-x}{(5-x)(-x)} =\frac{x-1 }{ x(x-5)}

We can clearly see in all of the factors in the expression the signs were changed correctly, but the result should have been preceeded with a negative sign, because it makes 3 (odd number) negatives, resulting in a negative expression. The correct form is

\displaystyle \frac{1-x}{(5-x)(-x)} =-\frac{x-1 }{ x(x-5)}

Now for the second expression

5/s+2/5=2/s

Let's arrange into format

\displaystyle \frac{5}{s}+\frac{2}{5} =\frac{2}{s}

It's a clear mistake because it was asssumed a product of fractions instead of a SUM of fractions. If the result was correct, then the expression should have been

\displaystyle \frac{5}{s}\times \frac{2}{5} =\frac{2}{s}

6 0
3 years ago
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