Hello,
I suppose as we don't see correctely the 2nd image, that it is the first one.
Angles DOY and DKY intersept then same arc are equals.
5x+15=3x+21
==>2x=6
==>x=3 and 5x+15=5*3+15=30°, 3x+21=3*3+21=30°
Angle OYK=15x=15*3=45°
Angle ODK=9x+18=9*3+18=45° =Angle OYK which intersept the same arc.
They are the same because the distance formula depends on a right triangle relationship between x and y, where as the right triangle has the same relationship with x being one leg of the right triangle and y the other leg of the right triangle
The model of the bridge and the actual bridge are similar solids. The lengths of corresponding sides of similar figures are in proportion.
5/25 = 6/30 = 8/40 = 1/5
Answer: 1/5
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
y = -1.5x -1
Step-by-step explanation:
moves right 8
and down 12
so m = -12/8x or -1.5x
(4,-7) moves up 6, (0, -1)
