Solve th2.5+X= 0.304x
1 answer:
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The complete question in the attached figure
we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm
the answer is
FE=6 cm </span>
we know that
1) <span>The triangles that are formed in the hexagon by joining all the vertices with the center of the hexagon are all equilateral and are equal in size
therefore
the radius of the circle is equals to the length side of the regular hexagon
FE=BP--------> FE=6 cm
the answer is
FE=6 cm </span>
Answer:
46
Step-by-step explanation:
With those problems if you are not given a picture is good we draw one.
Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then
m < XVY = m < YVW
2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms
2x-x = 15-7, combine like terms
x = 8
From the picture and the given we see that
m < XVW = m < XVY + m < YVW
m < XVW = 2x+7 + x+15 , combine like terms
m < XVW = 3x + 22, substitute x for 8
m < XVW = 3*8 + 22
m < XVW = 46
Check our work:
m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23
m < YVW = x+15 = 8 +15 = 23
m < XVW = m < XVY + m < YVW = 23+23 =46
