Answer:
∠EFH = 21°
∠HFG = 62°
∠EFG = 83°
Step-by-step explanation:
The diagram showing the angles has been attached to this response.
From the diagram, it can be deduced that;
Angle EFG = angle EFH + angle HFG
=> ∠EFG = ∠EFH + ∠HFG -------------------(i)
From the question:
∠EFH = (5x + 1)° -------------(ii)
∠HFG = 62° -------------(iii)
∠EFG = (18x + 11)° -------------(iv)
<em>Substitute these values into equation (i) as follows;</em>
(18x + 11) = (5x + 1) + 62
=> 18x + 11 = 5x + 1 + 62
<em>Collect like terms and solve for x</em>
18x - 5x = 1 + 62 - 11
13x = 52
x = 4
Now, to get each measurement, substitute x = 4 into each of equations (ii) - (iv)
∠EFH = (5x + 1)°
∠EFH = (5(4) + 1)°
∠EFH = (20 + 1)°
∠EFH = 21°
∠HFG = 62° [<em>Does not depend on x</em>]
∠EFG = (18x + 11)°
∠EFG = (18(4) + 11)°
∠EFG = (72 + 11)°
∠EFG = 83°
<u>Conclusion:</u>
∠EFH = 21°
∠HFG = 62°
∠EFG = 83°
Answer:
yes
Step-by-step explanation:
have a nice day
Answer:
12
Step-by-step explanation:
t/9=16/12
12t=144
t=12
The answer is C multiply 3x2 and multiply 4x3 then add hope that helps
Answer:
25.5 mph
Step-by-step explanation:
So Bradley's speed can be modeled by the equation y=2x+40 where y=speed, x=time in hours after noon, and b=initial speed
So 12:15 is 15 minutes after noon, which is also 0.25 or 1/4 of an hour after noon. This is the x-value. Plug this into the equation to get his speed at 12:15
y=2(0.25)+40
y=0.5+40
y=40.5
So his speed was 40.5 at the time and since he was going 15 miles over the speed limit, the speed limit is 15 less than his speed
40.5 - 15 = 25.5