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ale4655 [162]
3 years ago
6

The length of the rectangular field is two times its breadth. If the perimeter of the field is 300m, find the length and breadth

.
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0

Answer:

Youu can call the breadth x and then, as the length is two times the breadth, it would be 2x.

So now when we call x to the breadth and 2x to the length we can do an equation, as we know the sum of the four sides is 300 meters, so

2x + 2x + x + x = 300

6x = 300

x = 300/6 = 50

We know that the breadth is 50m, and, the length, which is twice the breadth, would be 100m in this exercise.

SO in this case, the breadth is 50 meters and the length is 100 meters..

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Answer:

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Step-by-step explanation: its 2 6\7

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2 years ago
Find the distance between the given points (2,8) and (7,7)
Ray Of Light [21]

Answer:

d=\sqrt{26}\approx5.0990

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula.

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Let (2,8) be x₁ and y₁ and let (7,7) be x₂ and y₂. Thus:

d=\sqrt{(7-2)^2+(7-8)^2}

Simplify:

d=\sqrt{5^2+(-1)^2}

Square:

d=\sqrt{25+1}

Add:

d=\sqrt{26}\approx5.0990

And that's our answer :)

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3 years ago
Write (4n^4)^2 without exponents
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Answer:

(4nx4nx4nx4n)x(4nx4nx4nx4n)

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Rewrite the quadratic function in vertex form.<br> Y=3x^2-12x+4
chubhunter [2.5K]

Answer:

\large\boxed{y=3(x-2)^2-8}

Step-by-step explanation:

The vertex form of an equation of a parabola y = ax² + bx + c:

f(x)=a(x-h)^2+k

(h, k) - vertex

h=\dfrac{-b}{2a},\ k=f(h)

We have the equation:

y=3x^2-12x+4\\\\a=3,\ b=-12,\ c=4

Substitute:

h=\dfrac{-(-12)}{2(3)}=\dfrac{12}{6}=2\\\\k=f(2)=3(2^2)-12(2)+4=3(4)-24+4=12-24+4=-8

Finally:

y=3(x-2)^2+(-8)=3(x-2)^2-8

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