Answer:
D
Step-by-step explanation:
![f(x)=(x-1)(x^2+2)^3\\f'(x)=(x-1)*3(x^2+2)^2*2x+(x^2+2)^3*1\\f'(x)=6x(x-1)(x^2+2)^2+(x^2+2)^3\\f'(x)=(x^2+2)^2[6x^2-6x+x^2+2]\\f'(x)=(x^2+2)^2(7x^2-6x+2)\\D](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x-1%29%2A3%28x%5E2%2B2%29%5E2%2A2x%2B%28x%5E2%2B2%29%5E3%2A1%5C%5Cf%27%28x%29%3D6x%28x-1%29%28x%5E2%2B2%29%5E2%2B%28x%5E2%2B2%29%5E3%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%5B6x%5E2-6x%2Bx%5E2%2B2%5D%5C%5Cf%27%28x%29%3D%28x%5E2%2B2%29%5E2%287x%5E2-6x%2B2%29%5C%5CD)
Hello,
y=5/(6x-72)
==>6x-72≠0
==>x≠72/6
==>x≠12
Answer:
2×25
THE ANSWER TO IT WOULD BE 50
Step-by-step explanation:
So if you distribute 4 in the first parentheses, you get 12x+20y+8z.
Then you distribute 3 in the second parentheses. You'll get 3x-3z. That all equals 12x+20y+8z+3x-3z.
Now you have to start combining numbers with the same variable. Start with x. 12x+3x is 15x.
y has no other common variable, it's left alone.
8z-3z is 5z
All together now with the numbers in simpler form, the equation is 15x+20y+5z
Jenna's would be the right answer because when you distribute 5 in her answer you get 15x+20y+5z
The answer for rounding 19.25 to the nearest ones place is 19.
