an aircraft carrier made a trip to Guam and back. the trip there to three hours and the trip back took four hours. it averaged 6
1 answer:
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Answer:
The probability that the maximum speed is at most 49 km/h is 0.8340.
Step-by-step explanation:
Let the random variable<em> </em><em>X</em> be defined as the maximum speed of a moped.
The random variable <em>X</em> is Normally distributed with mean, <em>μ</em> = 46.8 km/h and standard deviation, <em>σ</em> = 1.75 km/h.
To compute the probability of a Normally distributed random variable we first need to convert the raw score of the random variable to a standardized or <em>z</em>-score.
The formula to convert <em>X</em> into <em>z</em>-score is:
Compute the probability that the maximum speed is at most 49 km/h as follows:
Apply continuity correction:
P (X ≤ 49) = P (X < 49 - 0.50)
= P (X < 48.50)
*Use a <em>z</em>-table for the probability.
Thus, the probability that the maximum speed is at most 49 km/h is 0.8340.
Given:
The system of inequalities:
To find:
The point that represents a solution to the system by using the graph.
Solution:
We have,
The related equations of these inequalities are:
The line is a vertical line that intersect the x-axis at 3.
The table of values for is:
x y
0 -5
1 -3
Plot (0,-5) and (1,-3) on a coordinate plan and connect them by a straight line.
The boundary lines are dotted lines because the points on the lines are not included in the solution set.
Check the inequalities for (0,0).
First inequality: ( False)
Second inequality:
(False)
Both inequalities are false for (0,0). It means the shaded region of the lines is in the opposite direction of (0,0).
Plot the shaded region and the points (-3, -1), (1, 11), (4, -1), (5, 6) as shown in the below graph.
From the below graph, it is clear that the point (4,-1) is the only point lies in the common shaded region. So, (4,-1) represents a solution to the system.
Therefore, the correct option is C.
Answer: The mistake is improper use of distribution property.
Step-by-step explanation:
It is given that .
We need to find the mistake.
The given expression is
Using distribution property, we get
So, .
In the given calculation the 3 is not distributed properly because 3 is not multiplied with 2.
Therefore, the mistake is improper use of distribution property.