Answer:
Option E.
Step-by-step explanation:
The given expressions are
and
.
![x^2y^2=x\times x\times y\times y](https://tex.z-dn.net/?f=x%5E2y%5E2%3Dx%5Ctimes%20x%5Ctimes%20y%5Ctimes%20y)
![xy^3=x\times y\times y\times y](https://tex.z-dn.net/?f=xy%5E3%3Dx%5Ctimes%20y%5Ctimes%20y%5Ctimes%20y)
Greatest common factor of
and
is
![GCF=x\times y\times y=xy^2](https://tex.z-dn.net/?f=GCF%3Dx%5Ctimes%20y%5Ctimes%20y%3Dxy%5E2)
It is given that the greatest common factor of
and
is 45.
![xy^2=45](https://tex.z-dn.net/?f=xy%5E2%3D45)
![x=\dfrac{45}{y^2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B45%7D%7By%5E2%7D)
x and y are positive integers.
For y=45,15,9,5 ![x=\dfrac{45}{y^2}\notin Z^+](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B45%7D%7By%5E2%7D%5Cnotin%20Z%5E%2B)
Only for y=3,
![x=\dfrac{45}{3^2}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B45%7D%7B3%5E2%7D)
![x=\dfrac{45}{9}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B45%7D%7B9%7D)
![x=5 \in Z^+](https://tex.z-dn.net/?f=x%3D5%20%5Cin%20Z%5E%2B)
The possible value of y is 3.
Therefore, the correct option is E.
Answer:
I'm so sorry but I don't know this problem. I'm still in middle school so I haven't learned this yet. I wish I could help. ):
(w - 6)(w + 2)
w^2 + 2w - 6w - 12 =
w^2 - 4w - 12 <===
43!!!!! jahshwhwhwhehhehehehehehehehehehehehshehehehhehehehshshshhehehehe
We'll use the formula for the classical probability as follows.
P(A) = Number of outcomes favorable for A / Total number of possible outcomes
In this case, two socks are randomly drawn from a set of 6+10 = 16 socks. So the total number of possible outcomes = 16C2 = 120.
The two stocks match each other if they are both blue or grey. So the number of favorable outcomes is 6C2 + 10C2 = 15 + 45 = 60.
Hence the probability that the two stocks match is
![\frac{60}{120}=0.5](https://tex.z-dn.net/?f=%20%5Cfrac%7B60%7D%7B120%7D%3D0.5%20)
.