The distance between the two points is 
The polar coordinate of A is 
The polar coordinate of B is 
Explanation:
The two points are
and 
The distance between two points is given by,

Thus, the distance between the two points is 
The polar coordinates of A can be written as 
Distance = 
Substituting
, we get,
Distance = 

To make the angle positive, let us add 360,

The polar coordinate of A is 
Similarly, The polar coordinate of B can be written as 
Distance = 
Substituting
, we get,
Distance = 

To make the angle positive, let us add 360,

The polar coordinate of B is 