Answer: option B. it has the highest y-intercept.
Explanation:
1) point -slope equation of the line
y - y₁ = m (x - x₁)
2) Replace (x₁, y₁) with the point (5,3):
y - 5 = m (x - 3)
3) Expand using distributive property and simplify:
y - 5 = mx - 3m ⇒ y = mx + 5 - 3m
4) Compare with the slope-intercept equation of the line: y = mx + b, where m is the slope and b is the y-intercept
⇒ slope = m
⇒ b = 5 - 3m = y - intercept.
Therefore, for the same point (5,3), the greater m (the slope of the line) the less b (the y-intercept); and the smaller m (the slope) the greater the y - intercept.
Then, the conclusion is: the linear function with the smallest slope has the highest y-intercept (option B).
Answer:
A. Fail to reject the claim that the average math SAT score is 498 when in fact it is not 498.
Step-by-step explanation:
Type II Error:
A type II error happens when there is a non-rejection of a false null hypothesis.
In this question:
The null hypothesis is H0:μ=498.
Since there is a type II error, there was a failure to reject the claim that the average math SAT score is 498 when in fact it is not 498, and thus, the correct answer is given by option A.
Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
-4 isn't a real number because there is no square root of -4. However, there is a cube root of -8, because -2 * -2 * -2 = -8.
<em>CA </em>⁻¹ is undefined because there are more columns in <em>A </em>⁻¹ than there are rows in <em>C</em>.
