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2 years ago

There are 12 dogs and 6 cats at a local pet store. What is the ratio of the number of cats to the total number of animals?

Mathematics

2 answers:

Strike441 [17]2 years ago

6 0

Answer:

1:3

Step-by-step explanation:

1) The number of cats: 6

2) The number of all of the animals: 18

3) The ratio--> 6:18

4) Simplify: (both of the numbers go into six) thus, the answer is 1:3

Hope this helps :)

Dominik [7]2 years ago

5 0

Answer:

6:18

Step-by-step explanation:

1. The total amount of animals is 18

2. The amount of cats is 6

3. The ratio of cats to the total number of animals is 6:18

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Harrizon [31]

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3 years ago

40 points to whoever can answer for me!

luda_lava [24]

Answer:

x≤-3 2 ≤x<7

Step-by-step explanation:

(x^2+x-6) /(x-7) ≤0

Factor the numerator

(x+3)(x-2) / (x-7)≤0

Critical points are

X =-3 X =2 X=7

We need to check the values when

x≤3 -3 ≤ x≤2 2 ≤x<7 x>7

(x cannot be 7 because then the denominator is zero)

and see when it is less than 0

Substitute a value in and see if factor is positive or negative

x≤-3

(negative)(negative) / (negative) = negative

-3 ≤x≤2

(positive)(negative) / (negative) = positive this range does not work

2 ≤x<7

(positive)(positive) / (negative) = negative

x>7

(positive)(positive) / (positive)

8 0

3 years ago

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A laboratory technician needs to make a 63-liter batch of a 20% acid solution How can the laboratory technician combine a batch

Gre4nikov [31]

Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
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a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6

Let's solve this system of 2 equations:

x + y =63
x + 0.1 y = 12.6

Solving it will give you:

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3 years ago

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A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

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So, the value of quantity after 1 month, $q_1 = Q- r \times Q$