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3 years ago

How did I I get this wronggggggg

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

Answer:

mhmmm well i don't know what you got wrong but it was prob cus u didnt sum wrong or wasn't paying attention to what you were doing. Hope this helpss have a safe and joyful holiday

Step-by-step explanation:

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PLEASE HELP SOLVE! FIRST TO SOLVE RIGHT WILL GET BRAINIEST

IrinaVladis [17]

Answer:

40π/3 cm^2

Step-by-step explanation:

The centerline of the shaded region has a radius of 3 +4/2 = 5 cm. Its length is 1/3 of a circle with that radius, so is ...

length of centerline = (1/3)(2π·5 cm) = (10/3)π cm

The shaded region is 4 cm wide, so the area is the product of that width and the centerline length:

(4 cm)(10/3 π cm) = 40π/3 cm^2

3 0

3 years ago

Ms. May has to pay $5 for each bag of flour to make her cookies. She needs to buy 20 bags of flour. How much will she have to pa

xenn [34]

$100 dollars will be the end price.

5 0

3 years ago

Hillary pours 10 cups of orange juice into glasses that hold 1 2/3 cup each. How many glasses does Hillary fill?

Svetach [21]

$10 = \frac{30}{3 } \\ 1 + \frac{2}{3} = \frac{5}{3} \\ \frac{30}{3} \div \frac{5}{3} = \frac{30}{3} \times \frac{3}{5} = 8glasses$

3 0

3 years ago

Explain why 0.04/3.6 has the same answer as 4/360

lisov135 [29]

Because when you divide you get the same answer or something to do with percents

7 0

3 years ago

Is the binomial a factor of the polynomial nominal function?

Sedbober [7]

The factors for given equation f(x)= $x^{3} +3x^{2} -25x-75$ .

(x-1) - No
(x-3) - No
(x+3) - Yes
(x-5) - Yes
(x+5) - Yes

<u>Step-by-step explanation:</u>

The given equation is f(x)= $x^{3} +3x^{2} -25x-75$ .

Add 0 at the end of the equation.

$x^{3} +3x^{2} -25x-75$ = 0.

Let us group the given equation,

$(x^{3} +3x^{2}) -(25x-75)$ =0.

⇒ Group 1: $x^{3} +3x^{2}$ .

Group 2: $- 25x +75$ .

Pull out factor from each group,

⇒ Group 1: $(x+3)(x^{2})$ .

Group 2: (x+3) (-25).

Join the two group since both (x+3) is common in both groups.

$(x+3)(x^{2} -25)$ =0.

One of the factor is (x+3).

Other factors are solved by the formula, $a^{2}-b^{2} = (a+b) (a-b)$ .

$(x+3)(x^{2} -25)$ = (x+5) (x-5) .

The other factors are (x+5) and (x-5).

7 0

3 years ago