We set up a proportion: 24/?= 60/100
Cross multiply: 60*?= 24*100
⇒ ?= 24*100/60= 40
Dallas earned $40~
Answer:
Step-by-step explanation:
We will use the standard formula for half-life:
Where A₀ is the initial amount, a is the half-life, d is the time for one half-life, and t is the number of days.
So, we will substitute 1/2 for a and 24.3 for d. This yields:
We have a 3 gram sample. Therefore, our initial amount A₀ is 3:
And we want to find the remaining sample after 10 days. So, t=10. Substitute:
Use a calculator. So:
Therefore, for a 3 gram sample of Phosphorous-32 with a half-life of 24.3 days, after 10 days, there will be approximately 2.255 grams remaining.
Answer:
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Step-by-step explanation:
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Standard Form is ...
ax + by = c
where a ≥ 0, b > 0 (if a=0), and {a, b, c} are mutually prime integers (unless irrational numbers are involved).
You can get there from where you're starting in a couple of steps. Multiply by the least common denominator of any fractions. (Here, you multiply by 4.) Then put the variable terms on the opposite side from the constant term. Make sure the leading coefficient is positive.
... 4y -4 = x -12
... x -4y = 8 . . . . add 12-4y
5*23*2
5 x 23 x 2
115 x 2
230
total 230
