Answer: £485
Step-by-step explanation: Given that the rate is $3.20 to £1.
Exchange of $1,600 will be
1600/3.20 = £500
With commission on 3%
3/100 × 500 = 15
Take away £15 from £500
500 - 15 = 485
Answer:c
Step-by-step explanation:
The first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
<em><u>Solution:</u></em>
Let x = gallons consumed by car 1
Let y = gallons consumed by car 2
Fuel efficiency of car 1 = 15 miles per gallon
Distance covered in 1 gallon of gas = 15 miles
Fuel efficiency of car 2 = 25 miles per gallon
Distance covered in 1 gallon of gas = 25 miles
<em><u>Given a total gas consumption of 70 gallons</u></em>
Therefore,
gallons consumed by car 1 + gallons consumed by car 2 = 70
x + y = 70 ------ eqn 1
<em><u>The two cars went a combined total of 1350 miles</u></em>
Therefore,
gallons consumed by car 1 x distance covered in 1 gallon of gas of car 1 + gallons consumed by car 2 x distance covered in 1 gallon of gas of car 2 = 1350

15x + 25y = 1350 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
x = 70 - y ------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
15(70 - y) + 25y = 1350
1050 - 15y + 25y = 1350
10y = 1350 - 1050
10y = 300
y = 30
<em><u>Substitute y = 30 in eqn 3</u></em>
x = 70 - 30
x = 40
Thus first car consumed 40 gallons of gas and second car consumed 30 gallons of gas
Answer:
$1954
Step-by-step explanation:
Given the profit function expressed as;
y=-3x^2 + 197x –
1279
The profit is at maximum when dy/dx = 0
dy/dx = -6x + 197
0 = -6x+197
6x = 197
x = 197/6
x = 32.83
substitute 32.83 into the modeled function
y=-3x^2 + 197x –
1279
y -3(32.83)²+197(32.83) - 1279
y = -3(1,078.03)+6,467.51 - 1279
y = -3,234.09+6,467.51-1279
y = 1,954.42
hence the maximum amount of profit the company can make, to the nearest dollar is $1954
B(x) = x + 41
B(-10) = -10 + 41
B(-10) = 31 [Answer]