Find the sum of the geometric sequence.

Mathematics

1 answer:

Rama09 [41]3 years ago

5 0

<u>Answer:</u>

$\frac{31}{3}$

<u>Step-by-step explanation:</u>

We are given the following geometric sequence and we are to find its sum:

$\frac{1}{3} + \frac{2}{3} + \frac{4}{3} + \frac{8}{3} + \frac{16}{3}$

For this, we just simply need to add these fractions by taking their LCM.

Since the denominator is same for all the fractions in the geometric sequence, we can take the same denominator and add all the numbers in the numerator to get:

$\frac {1 + 2 + 4 + 8 + 16 } {3}$ $= \frac{31}{3}$

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Explanation:

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Answer:

Option B - False

Step-by-step explanation:

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The answer to this problem?

LenaWriter [7]

The simplified expression of $\sqrt{\frac{162x^9}{2x^{27}}}$ is $\frac{9}{x^9}$