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Bezzdna [24]
3 years ago
8

Do earthquakes ever happen in Malaysia?​

Computers and Technology
1 answer:
adoni [48]3 years ago
8 0

The correct answer to this open question is the following.

Although there are no options attached we can say the following.

Do earthquakes ever happen in Malaysia?

Yes, they do. And they are very frequent and high in intensity.

For instance, the Sabah earthquake in 2015.

On June 5, 2015, the region of Malaysia was hit by a strong earthquake, 6.0 of magnitude on the Ritcher scale. The telluric movement lasted 30 seconds and caused much destruction.

Experts and scientists confirm that this had been the strongest earthquake since the one presented in 1976.

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MakcuM [25]

Answer:

all but 3

Explanation:

3 is strange and I need points sorry

5 0
3 years ago
Read 2 more answers
Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T
hammer [34]

Answer:

In C++:

#include<iostream>

#include<vector>

using namespace std;

int main() {

int len;

cout<<"Length: ";  cin>>len;

string inpt;

vector<string> vect;

for(int i =0;i<len;i++){

   cin>>inpt;

   vect.push_back(inpt); }

char ch;

cout<<"Input char: ";  cin>>ch;  

for(int i =0;i<len;i++){

   size_t found = vect.at(i).find(ch);  

       if (found != string::npos){

           cout<<vect.at(i)<<" ";

           i++;

       }

}  

return 0;

}

Explanation:

This declares the length of vector as integer

int len;

This prompts the user for length

cout<<"Length: ";  cin>>len;

This declares input as string

string inpt;

This declares string vector

vector<string> vect;

The following iteration gets input into the vector

<em>for(int i =0;i<len;i++){ </em>

<em>    cin>>inpt; </em>

<em>    vect.push_back(inpt); } </em>

This declares ch as character

char ch;

This prompts the user for character

cout<<"Input char: ";  cin>>ch;  

The following iterates through the vector

for(int i =0;i<len;i++){

This checks if vector element contains the character

   size_t found = vect.at(i).find(ch);  

If found:

       if (found != string::npos){

Print out the vector element

           cout<<vect.at(i)<<" ";

And move to the next vector element

           i++;

       }

}  

4 0
3 years ago
What will the following code print out: int numbers [] = {99, 87, . 66, 55, 101}; for (int i = 1; i &lt; 4; i++) cout &lt;&lt; n
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Answer:

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the array show a decimal value .66, i assume this is enter by mistake because option has no decimal value.

The index of the array is start from zero, it means the first element store in the array at position zero.

In the for loop the variable 'i' start from 1 not zero and it goes to i<4 means i=3.

So, it access the element from 2 to 4 because the index is position of element less than 1.

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Bluetooth is the most reasonable answer
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Answer:

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Explanation:

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