X(2x²-9x+10)=x(2x-5)(x-2)=0.
x=0 is one solution.
2x-5=0 and x-2=0 give us the solutions x=5/2 and x=2.
So x=0, 2 or 5/2.
Answer: 357 cm²
Step-by-step explanation: In this problem, were asked to find the area of the trapezoid shown. Remember that a trapezoid is a quadrilateral with one pair of parallel sides. The formula for the area of a trapezoid is shown below
The b's are the bases or the parallel sides and the h represents the height.
So in the trapezoid shown, the bases are 15 cm and 27 cm and the height is 17 cm.
Plugging this information into the formula, we have .
Next, the order of operations tells us that we must simplify inside the parentheses first. 15 cm + 27 cm is 42 cm and we have
1/2 × 42 cm is 21 cm and we have (21 cm)(17 cm) which is 357 cm².
So the area of the trapezoid shown is 357 cm².
Answer:
x = √2 + 2, -√2 + 2
Step-by-step explanation:
y = -2(x-2)² + 4
-2(x-2)² + 4 = 0 --- replace y with 0
-2(x - 2)² = -4 --- subtract 4 from both sides
(x - 2)² = 
--- divide both sides by -2
(x - 2)² = 2 --- simplify
x - 2 = +-√2 --- square root both sides
x - 2 = √2 --- split into 2 equations
x - 2 = -√2
x = √2 + 2 --- solve first equation
x = -√2 + 2 --- solve second equation
x = √2 + 2, -√2 + 2
Find the area of the square first
Area = Length x Width
Area = 12 x 9
Area = 108
Find the area of the right triangles
Area = 1/2(Length x Base)
Area = 1/2(9 x 2)
Area = 1/2(18)
Area = 9
Since there is 2 triangles multiply by 2
9 x 2 = 18
Now add
108 + 18 = 126
126 is your area
Answer:
The identity property
Step-by-step explanation:
anything added to 0 is itself.
