Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Step-by-step explanation:
Total number of students = 8
Number of student who has passed Exam P/1 = 1
Number of student who has passed Exam FM/2 = 1
No student has passed more than one exam.
According to question, exactly three students from a randomly chose group of four students have not passed Exam P/1 or Exam FM/2.
So, Probability will be

Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.
Hello,
In my old memories,
p(μ-2σ<=X<=μ+2σ)=95%
p(μ-3σ<=X<=μ+3σ)=99%
1000-2*200=1000-400=600
1000+2*200=1000+400=1400
Answer A
Answer:
–9t − 19t + 9t − –18t − t = 14
t = -7
Step-by-step explanation:
Hope this helps!!