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dangina [55]
3 years ago
15

Can someone please answer this

Mathematics
1 answer:
kaheart [24]3 years ago
8 0

Answer:

<h2>{7}^{3} (as \: a \: single \: power \: of \: 7)</h2>

Step-by-step explanation:

<em><u>Given</u></em><em><u> </u></em><em><u> </u></em>

{7}^{4}  \div 7

<em><u>Since</u></em><em><u>,</u></em>

{a}^{x}  \div  {a}^{y}  =  {a}^{x - y}

<em><u>Hence</u></em><em><u>,</u></em>

=  {7}^{4 - 3}

=  {7}^{3} (ans)(as \: a \: single \: power \: of \: 7)

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There are eight students in a class. Only one of them has passed Exam P/1 and only one of them has passed Exam FM/2. No student
Svetach [21]

Answer: There is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

Step-by-step explanation:

Total number of students = 8

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Number of student who has passed Exam FM/2 = 1

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So, Probability will be

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Hence, there is probability of 0.57 chances that exactly three students from a group of four students have not passed Exam P/1 or Exam FM/2.

4 0
3 years ago
(-7)-(-44)/22+((-4)*59) with calculation
Pavel [41]

Hi,

\frac{ ( - 7) - ( - 44)}{22 + (( - 4) \times 59)}

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good look :)

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Check my answer please?
Angelina_Jolie [31]
Hello,

In my old memories,
p(μ-2σ<=X<=μ+2σ)=95%
p(μ-3σ<=X<=μ+3σ)=99%


1000-2*200=1000-400=600
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Answer A



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Answer:

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Step-by-step explanation:

Hope this helps!!

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3 years ago
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