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Daniel [21]
2 years ago
12

17. Ms Steele is building a circular fountain, on the diagram 2 centimeters is equal to 5 feet. If

Mathematics
2 answers:
tiny-mole [99]2 years ago
7 0

Answer:

George Washingmachine

Step-by-step explanation:

kobusy [5.1K]2 years ago
6 0

Answer:

706.858 ft^{2} (3 d.p)

Step-by-step explanation:

Convert first:

12 \div 2 = 6

6 \times 5 = 30 ft

Area of circle = \pi r^{2}

= \pi (30\times \frac{1}{2})^{2}

= 225\pi

= 706.858 ft^{2}(3 d.p)

Hope this helps :)

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On what i need to see what you are talking bout so maybe i can answer it thank u please
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3 years ago
Use the situation below to complete the table and answer the questions,
Amiraneli [1.4K]

Answer:

t = 13

Step-by-step explanation:

3 months ------ 4500

6 months ------ x

3/6 = 4500/x

cross multiplation:

3x =27000

x = 9000,or we should have just doubled the wages, since the time doubled

3 months ------ 4500

5 months ------ y

3/5 = 4500/y

3y = 22500

y = 7500

3 months ------- 4500

t months -------- 19500

3/t = 4500/19500 = 3/13

3t = 39

t = 13

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2 years ago
people are waiting on line for a theater premiere. every 5th person in line will receive a free theater ticket. every 6th person
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The 30th person will
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The dimension of a rectangular pool are 24.5 feet by 13 feet. The depth of the water is 4 feet. Each cubic foot contains 7.48 ga
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Multiply length by width, and height. Than multiply the volume by 7.48 gal. Than you have the amount of water that can fill the whole pool. Than multiply by 0.8. and subtract it from the original volume. 
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Suppose a certain airline uses passenger seats that are 16.2 inches wide. Assume that adult men have hip breadths that are norma
Pachacha [2.7K]

Answer:

Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.

There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem

Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that \mu = 14.4, \sigma = 1.1.

What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?

For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{1.1}

Z = 1.64

Z = 1.64 has a pvalue of 0.9495.

This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.

For the average of the sample

What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?

Now, we need to find the standard deviation of the sample before using the zscore formula. That is:

s = \frac{\sigma}{\sqrt{110}} = 0.1.

Now

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.2 - 14.4}{0.1}

Z = 18

Z = 18 has a pvalue of 0.9999.

This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.

7 0
3 years ago
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