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Delicious77 [7]
3 years ago
8

Kylie wants to add 10 to 167. She thinks that the 6 represents the number of tens and thats by adding a 10 there are a total of

7 tens. Kylie believes the sum is 177. Which of the following is true about kylie's answer
Mathematics
1 answer:
Vladimir79 [104]3 years ago
3 0

Answer:

kylie is slow and so am i

Step-by-step explanation:

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What is the decimal multiplier to decrease by 3.4%?
olga nikolaevna [1]

Answer:

3.4%

=3.4/100

=0.034

Now,

1-0.034

0.966

0.966 is the multiplier

Step-by-step explanation:

8 0
2 years ago
The ratio of red marbles to blue marbles in a bag is 3:4 . If there are 42 marbles in the bag. how many marbles are red?
PolarNik [594]

Answer:

18 marbles

Step-by-step explanation:

Step 1

Express the fraction of each type of marble as a function of the total number of marbles as shown;

Let;

total marbles=x

red marbles=3/(3+4)=3/7x

blue marbles=4/7 x

But x=42 marbles

The total number of marbles for each type can be expressed as;

total number of red marbles=fraction of red marbles×total number of marbles

where;

fraction of red marbles=3/7 x

total number of marbles=42

replacing;

total number of red marbles=(3/7)×42=18 marbles

total number of blue marbles=fraction of blue marbles×total number of marbles

where;

fraction of blue marbles=4/7 x

total number of marbles=42

replacing;

total number of blue marbles=(4/7)×42=24 marbles

5 0
2 years ago
Carl wants to plant a garden that is 1 1/2 and has an area of 3 1/2 square yards. how wide should it be
yan [13]
It should be 2.33333.... wide. Hope it help!
4 0
3 years ago
Which could be the function graphed below?
madam [21]

f(x)=\sqrt{x} -2 is the correct option

3 0
3 years ago
Use Definition 7.1.1. DEFINITION 7.1.1 Laplace Transform Let f be a function defined for t ≥ 0. Then the integral ℒ{f(t)} = [inf
Alla [95]

f(t)=\begin{cases}-1&\text{for }0\le t

Write f(t) in terms of the unit step function u(t):

f(t)=-1(u(t)-u(t-1))+1u(t-1)=2u(t-1)-u(t)

where

u(t)=\begin{cases}1&\text{for }t\ge0\\0&\text{for }t

Then the Laplace transform of f(t), denoted F(s), is

F(s)=\displaystyle\int_0^\infty f(t)e^{-st}\,\mathrm dt

F(s)=\displaystyle2\int_1^\infty e^{-st}\,\mathrm dt-\int_0^\infty e^{-st}\,\mathrm dt

\implies F(s)=\dfrac{2e^{-s}}s-\dfrac1s=\dfrac{2e^{-s}-1}s

3 0
3 years ago
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