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Tpy6a [65]
3 years ago
14

Please help, I'm in a test! Question is in the image attached! if you think you could help me out more, let me know and I'll pos

t more questions like this! ​

Mathematics
2 answers:
lina2011 [118]3 years ago
5 0

Answer:

180%

Step-by-step explanation:

took the test got it right on the test

Gre4nikov [31]3 years ago
3 0

Answer:

180° (in place of blank)

Step-by-step explanation:

<u><em>GIVEN</em></u><em> :-</em>

  • ∠D = 127°
  • ∠A = 75°

<u><em>PROCEDURE</em></u><em> :-</em>

∠C & ∠D are linear pair. (∵ They lie on same line)

⇒ ∠C + ∠D = 180°

⇒ ∠C = 180° - 127°

In a triangle , sum of its all interior angles equals to 180° (which is also known as "Angle Sum Property). So,

∠A + ∠B + ∠C = 180°

⇒ 75° + ∠B + (180° - 127°) = 180°

⇒ ∠B = 180° - 75° - (<u>180°</u> - 127°)

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Convert from rectangular to polar coordinates: note: choose rr and θθ such that rr is nonnegative and 0≤θ&lt;2π0≤θ&lt;2π (a)(9,0
DochEvi [55]

Answer:

Step-by-step explanation:

Convert rectangle (x , y) to polar coordinates ( r , θ)

x=r  \cos \theta, y= r \sin \theta

r=\sqrt{x^2+y^2} , \theta =tan^-^1 (\frac{y}{x} )

a) converts (9, 0) to polar coordinates  ( r , θ)

r=\sqrt{x^2+y^2} \\\\=\sqrt{9^2+0} \\\\=9

\theta= \tan^-^1 (\frac{0}{9} )\\\\=0

b) Convert (18,\frac{18}{\sqrt{3} } ) to polar coordinates ( r, θ)

r = \sqrt{18^2+(\frac{18}{\sqrt{3} })^2 } \\\\=\sqrt{324+108} \\\\=\sqrt{432}

\frac{x}{y} \theta = \tan^-^1(\frac{\frac{18}{\sqrt{3} } }{18} )\\\\= \tan ^-^1(\frac{1}{\sqrt{3} } )\\\\= \frac{\pi}{6}

c)  converts (-5, 5) to polar coordinates  ( r , θ)

r =\sqrt{(-5)^2+(5)^2} \\\\=\sqrt{50} \\\\=5\sqrt{2}

\theta=\tan^-^1(\frac{5}{-5} )\\\\= \tan^-^1(-1)\\\\=\frac{3\pi}{4}

d)  converts (-1, √3) to polar coordinates  ( r , θ)

r=\sqrt{(-1)^2+(\sqrt{3})^2 } \\\\= \sqrt{4} \\\\=2

\theta=\tan^-^1(\frac{\sqrt{3} }{-1} )\\\=\tan^-^1(-\sqrt{3} )\\\\=\frac{2\pi}{3}

= \frac{2\pi}{\sqrt{3} }

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1. Use the figure below to answer the questions.<br><br> (a) Solve for x.
Dmitry [639]

Let's see what to do buddy...

_________________________________

The sum of the angles of each n-sided figure is found in the following equation :

(n - 2) \times 180

The question's figure is 5-sindes figure

so the sum the angles equal :

(5 - 2) \times 180 = 3 \times 180 = 540 \\

So we have :

90 + 107 + 144 + 138 + x = 54 0 \\

479 + x = 540

Subtract the sides of the equation minus 479

x = 540 - 479

x = 61

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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