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3 years ago

PLS HELP ASAP! GIVING BRAINLY

Mathematics

2 answers:

ioda3 years ago

4 0

The answer would be (x+1) and (x+10) so E

horsena [70]3 years ago

3 0

The answer is, the last option.

( x + 1)

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Simplify the expression: 5(1 + 8d)

Rina8888 [55]

Answer:

5 + 40 d

Step-by-step explanation:

Hey there,

To simply this you have to multiply each term in the brackets by 5.

$5(1+8d)$

$5+40d$

Further explanation

5 ( 1 + 8 d )

5 × 1 + 5 × 8 d

5 +40 d

Hope this helps you.

Let me know if you have any other question :-)

5 0

2 years ago

Read 2 more answers

Trevor Linden, a former player for the Vancouver Canucks, is 1.93 m tall. On a hockey card, he is 5.4 cm tall. What scale was us

Anastaziya [24]

Answer:

scale used to print the hockey card is 27/965

scale used to print the hockey card in decimal is 1/35.74

Step-by-step explanation:

we know that in scale problems

scale is used in drawing to enlarge or reduce size of object by a certain amount

scale = size of object in drawing/ actual size of object

Height of trevor = 1.93 m

we know that 1 m = 100 cm

Height of trevor in cm = 1.93 m*100 = 193 cm (actual size)

(this is done so that unit of measurement is same for card and trevor's height i.e cm)

Trevor's card on hockey card = 5.4 cm(size in drawing)

scale used = Trevor's card on hockey card /Height of trevor in cm

= 5.4/193 = 54/ 1930 = 27/965

scale used to print the hockey card is 27/965

scale used to print the hockey card in decimal is 1/35.74

7 0

4 years ago

1.) Simplify the expression.

miss Akunina [59]

Answer:

$sin ( u +\frac{\pi}{2} ) = cos (u)$

Step-by-step explanation:

Let us use the identity

sin(A+B)= cos(A) sin(B)+cos (B) sin(A) to simplify the given expression

Then

$sin(u + \frac{\pi}{2})= \cos \left(u\right)\sin \left(\frac{\pi }{2}\right)+\cos \left(\frac{\pi }{2}\right)\sin \left(u\right)$ --------------------(1)

Here

$cos (\frac{\pi}{2}) = 0\\$ ---------------------(2)

$sin(\frac{\pi}{2})= 1$ ---------------------(3)

Substituting the values in (1)

$sin(u + \frac{\pi}{2})= \cos \left(u\right)(1)+(0)\sin \left(u\right)$

$sin(u + \frac{\pi}{2})= \cos \left(u\right) + 0$

$sin(u + \frac{\pi}{2})= \cos \left(u\right)$

4 0

3 years ago

8. Which of the following equations represent the problem? a. 63 = h + 2(h) b. 63 = (h+2)h C. 63 = 2h + 2 d. 63 = h? + 2

Marta_Voda [28]

Answer:

no b 63=(h+2)

Step-by-step explanation:

this is your ans

5 0

3 years ago

A parabola passes through the points (-2,8), (0,2), and (1,5). What function does the graph represent?

zheka24 [161]

ANSWER

$y = 2 {x}^{2} + x + 2$

EXPLANATION

Let the function that represent the graph be:

$y = a {x}^{2} + bx + c$

The parabola passes through the points (-2,8), (0,2), and (1,5).

These points must satisfy the function.

For (-2,8), we have

$8= a{( - 2)}^{2} + b( - 2) + c$

This implies that that,

$4a - 2b + c = 8...(1)$

For (0,2), we have,

$2= a{( 0)}^{2} + b( 0) + c$

This implies that,

$c = 2$

For (1,5), we have

$5= a{( 1)}^{2} + b( 1) + c$

This implies that,

$a + b + c = 5...(2)$

Put c=2 into equation (1) and (2).

$4a - 2b + 2 = 8$

$4a - 2b = 8 - 2$

$4a - 2b = 6$

$2a - b = 3...(3)$

$a + b + 2=5$

$a + b =5 - 2$

$a + b = 3...(4)$

Add equation (3) and equation (4)

$3a = 6$

$a = 2$

Put a=2 into equation (4).

$2 + b = 3$

$b = 3 - 2 = 1$

Therefore the function is

$y = 2 {x}^{2} + x + 2$

5 0

4 years ago