Given that the height of the disc is modeled by the function:
h=-16t^2+20t+6
a] The maximum height will be as follows:
At maximum height:
h'(t)=0
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus the maximum height will be:
h(5/8)=-16(5/8)^2+20(5/8)+6
=12.25 ft
b] <span>How long will it take the disc to reach the maximum height?
</span>time taken to reach maximum height will be:
from h(t)
h'(t)=-32t+20=0
thus
t=20/32
t=5/8 sec
thus time taken to reach maximum height is t=5/8 sec
c]<span>How long does it take for the disc to be caught 3 feet off the ground?
</span>h(t)=-16t^2+20t+6
but
h(t)=3
thus
3=-16t^2+20t+6
solving for t we get:
0=-16t^2+20t+3
factoring the above we get:
t=5/8-/+√37/8
t=-1.5256 or 2.776
since there is no negative time we pick t=2.776
Hence time taken for the disc to be caught 3 ft from the ground is 2.776 ft
Answer:
X=12 on edg
Step-by-step explanation:
Answer:
Step-by-step explanation:
Area of garden = length * breadth = 90 * 75 = 6750 Sq . m
= 6750 / 1000 = 0.675 hectare
Area of path = 100 * 85 - 90 * 75
= 8500 - 6750 = 1750 Sq. m
All you have to is solve for Y.
Solve the exponent first
5^2 = 5 x 5 = 25
Then multiply 10 by 25
10 x 25 = 250
250 is your answer