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3 years ago

What is an overdraft fee? List two reasons why banks charge overdraft fees.

1 answer:

6 0

An overdraft fee is when you use all of your money from your bank account and then you keep buying stuff so your sing the banks money and your account is in the the negative and however much money you use after you start using the banks money is ow much money you have to pay back no matter the amount

You might be interested in

What additional info do you need

Novay_Z [31]

Answer:

∠C ≅ ∠M or ∠B ≅ ∠L

Step-by-step explanation:

You are given an angle and its opposite side as being congruent. AAS requires two congruent angles and one side, so you need another set of congruent angles (one in each triangle). It does not matter which they are. The above-listed pairs are appropriate.*

_____

* Since the figure cannot be assumed to be drawn to scale, either of angles B or C could be declared congruent to either of angles L or M. However, it appears that angles B and L are opposite the longest side of the triangle, so it makes good sense to declare that pair congruent. The same congruence statement (ΔBCD≅ΔLMN) would result from declaring angles C and M congruent. So, either declaration will work (matches the last answer choice.)

AAS requires two angles and a side. One side is already marked, so we do not need any more information about sides. (The second and third answer choices can be rejected as irrelevant.)

7 0

3 years ago

Find the measure of angle A

Sladkaya [172]

Answer:

40°

X=11

I can't give you a very good explanation because I'm

only a freshman lol, I only studied so far in this stuff so I think ill stick to questions like this that give me side lengths and require an angle.

Anyways, hope this helped!

4 0

3 years ago

What information is necessary to prove the triangles congruent by SAS?

Ber [7]

Answer:

SAS requires two congruent sides and the included angle be also congruent

Given is the picture are congruent triangles

ΔACB ≅ ΔECD, because:

AC ≅ EC, given
BC ≅ DC, given
∠ACB ≅ ∠ECD, vertical angles

5 0

2 years ago

Read 2 more answers

23 x 32 is the prime factorization for which one of these choices?

antoniya [11.8K]

<h2>Answer:</h2>

⟶ 2³ × 3² is the prime factorization for which one of these choices?

Let's check,

1) 6 = 3 × 2 [So, obviously not this choice]

2) 25 = 5 × 5 = 5² [Not this either]

3) 36 = 3 × 2 × 2 × 3 = 3² × 2² [Doesn't match with 2³ × 3²]

4) 72 = 2 × 2 × 2 × 3 × 3 = 2³ × 3² [Matches]

⟶ The answer is, choice 72.

$\underbrace{ \overbrace{ \mathfrak{Carry \: On \: Learning}}}$

3 0

2 years ago

Which situation will have the greatest number of permutations?

Anton [14]

Answer:

Option C will have greatest number of permutations.

Step-by-step explanation:

The number of license plates with 4 letters followed by 3 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

23 letter options for 4th letter.

So total options for 4 letters 26*25*24*23 = 358800

Now, 3 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

Total options for 3 numbers= 10*9*8 = 720

total options for 4 letters and 3 numbers will be: 358800 * 720 = 258,336,000

The number of license plates with 3 letters followed by 4 numbers, where letters and digits cannot be repeated.

We have total 26 letters (A_Z) and the letters can't be repeated. So we have 26 letter options for 1st letter

25 letters options for 2nd letter

24 letter options for 3rd letter

So total options for 3 letters= 26*25*24 = 15600

Now, 4 numbers are required. We have total 10 numbers (0-9)

10 number options for 1st number

9 number options for 2nd number

8 number options for 3rd number

7 number options for 4th number

Total options for 4 numbers = 10*9*8*7 = 5040

total options for 4 letters and 3 numbers will be: 15600 * 5040 = 78,624,000

C. The number of license plates with 4 letters followed by 3 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 4 letters and 10 options for each 3 numbers

26*26*26*26 *10*10*10 = 456,976 * 10,00 = 456,976,000

total options for 4 letters and 3 numbers will be: 456,976,000

The number of license plates with 3 letters followed by 4 numbers, where letters and digits can be repeated.

Now, the letters and digits can be repeated. So we have 26 options for each 3 letters and 10 options for each 4 numbers

26*26*26 *10*10*10*10 = 17,576 * 10,000 = 175,760,000

total options for 3 letters and 4 numbers will be: 175,760,000

So, Option C will have greatest number of permutations.

7 0

3 years ago