All categories

2 years ago

Which is not a zero of the following function!? f(x)=x3+3x2-x-3

Mathematics

1 answer:

nata0808 [166]2 years ago

3 0

Answer:

Step-by-step explanation:

You might be interested in

Todd has twice as many songs in his playlist as Vlad. Becca has three times as many songs in her playlist as Todd. If all three

nikitadnepr [17]

Answer:

Todd has 540540 songs in his playlist.

Vlad has 270270 songs in his playlist.

Becca has 162162 songs in her playlist.

Step-by-step explanation:

# of songs Todd has = T

# of songs Vlad has = V

# of songs Becca has = B

1) Todd has twice as many songs in his playlist as Vlad:

T=2V

2) Becca has three times as many songs in her playlist as Todd:

B=3T

3) All three people have a total of 243243 songs in their playlists:

T+V+B=243243

Because T=2V then you can substitute T as 2V in the second equation:

B=3(2V)

B=6V

Now in the final equation, you can substitute everything for V:

2V+V+6V=243243

9V=243243

V=27027

Now substitute for T:

T+1/2T+3T=243243

9/2T=243243

T=54054

Now substitute for B:

1/3B+1/6B+B=243243

3/2B=243243

B=162162

Check answers:

27027+54054+162162=243243

243243=243243

3 0

2 years ago

50 points! I understand A. and B. but I would really appreciate help with C.

FromTheMoon [43]

Answer:

$51.72\text{ cells per hour}$

Step-by-step explanation:

So, the function, P(t), represents the number of cells after t hours.

This means that the derivative, P'(t), represents the instantaneous rate of change (in cells per hour) at a certain point t.

So, we are given that the quadratic curve of the trend is the function:

$P(t)=6.10t^2-9.28t+16.43$

To find the instanteous rate of growth at t=5 hours, we must first differentiate the function. So, differentiate with respect to t:

$\frac{d}{dt}[P(t)]=\frac{d}{dt}[6.10t^2-9.28t+16.43]$

Expand:

$P'(t)=\frac{d}{dt}[6.10t^2]+\frac{d}{dt}[-9.28t]+\frac{d}{dt}[16.43]$

Move the constant to the front using the constant multiple rule. The derivative of a constant is 0. So:

$P'(t)=6.10\frac{d}{dt}[t^2]-9.28\frac{d}{dt}[t]$

Differentiate. Use the power rule:

$P'(t)=6.10(2t)-9.28(1)$

Simplify:

$P'(t)=12.20t-9.28$

So, to find the instantaneous rate of growth at t=5, substitute 5 into our differentiated function:

$P'(5)=12.20(5)-9.28$

Multiply:

$P'(5)=61-9.28$

Subtract:

$P'(5)=51.72$

This tells us that at exactly t=5, the rate of growth is 51.72 cells per hour.

And we're done!

7 0

2 years ago

19.4mm what the lower bound correct to 1dp

padilas [110]

Answer:

The lower bound of 19.4 is 19.35

6 0

2 years ago

Pick the equations that are equal to 15-8y=-11

Black_prince [1.1K]

Answer:

The equations that are equal to 15-8y=-11 are...

- Number 1

- Number 4

4 0

3 years ago

Read 2 more answers

Calculate the area of the circle. round your answer to the nearest hundredth

Artemon [7]

52 is the answer I believe

8 0

3 years ago