Answer:
J: 2/45
Step-by-step explanation:
You multiply the probabilities together then simplify
2/15 x 5/15
to get 10/225
simplify to get your answer of 2/45
Answer:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Step-by-step explanation:
If the question does not limit man to produce only one model of club, then the maximized profit of every condition produced under 50 sets daily will be all model A exclusive. such as $60 x 50 (model A) , even just produce 49 set that day, the maximal profit is still $60 x 49.
Re-consider the logic of the question ....
To solve for proportion we make use of the z statistic.
The procedure is to solve for the value of the z score and then locate for the
proportion using the standard distribution tables. The formula for z score is:
z = (X – μ) / σ
where X is the sample value, μ is the mean value and σ is
the standard deviation
when X = 70
z1 = (70 – 100) / 15 = -2
Using the standard distribution tables, proportion is P1
= 0.0228
when X = 130
z2 = (130 – 100) /15 = 2
Using the standard distribution tables, proportion is P2
= 0.9772
Therefore the proportion between X of 70 and 130 is:
P (70<X<130) = P2 – P1
P (70<X<130) = 0.9772 - 0.0228
P (70<X<130) = 0.9544
Therefore 0.9544 or 95.44% of the test takers scored
between 70 and 130.
I believe the answer is d
the answer is d not similar
