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Anon25 [30]
3 years ago
12

For what values of a and m does f(x) have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1? f(x)=2x^m/x+a {a =

–1, m = 1}
Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

f(x)=\frac{2x^{m} }{x+a}

f(x)=\frac{2x^{1} }{x-1}

If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.

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For light: Inverse Square Law 

<span>
The signal is weaken by the inverse square of the difference of distances this means that one over the square of the difference. </span>

<span>
</span>

Therefore, 70000LY / 141 LY =496.45 and that squared =246462.602 times less signal, or 1/246462.602.


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The new telescope needs 246462.60 times that area to have enough sensitivity </span>

<span>
<span>(150 x 150 x Pi) = 70 685 sq m area for the Arecibo telescope and that times 246462.60
= 1.74212 x 10^10</span></span>

<span><span>
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