Question

For what values of a and m does f(x) have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1? f(x)=2x^m/x+a {a = –1, m = 1}

Answer 1

Answer:

See below

Step-by-step explanation:

$f(x)=\frac{2x^{m} }{x+a}$

$f(x)=\frac{2x^{1} }{x-1}$

If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.