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Anon25 [30]
3 years ago
12

For what values of a and m does f(x) have a horizontal asymptote at y = 2 and a vertical asymptote at x = 1? f(x)=2x^m/x+a {a =

–1, m = 1}
Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

See below

Step-by-step explanation:

f(x)=\frac{2x^{m} }{x+a}

f(x)=\frac{2x^{1} }{x-1}

If x=1, then 1-1=0, which implies a vertical asymptote at x=1 since dividing by 0 is undefined.

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Patrick says that .500 is greater than .50 and .5 is he correct?
Dafna1 [17]
No he is not  .500, .50 and .5 are all the same number.

8 0
3 years ago
Parabolas. Please help me
olganol [36]
  1. x² = 16 y
  2. x = 0
  3. (x + 4)² = 2/3 (y - 2)
  4. Gayle identifies that the vertex of the parabola is <u>(3, -1)</u> . The parabola opens <u>right</u>, and the focus is <u>3 </u>units away from the vertex. The directrix is <u>6 </u>units from the focus. The focus is the point <u>(6, -1)</u>. The directrix of the equation is <u>x = 0.</u>
  5. (y - 6)² = 4p (x - 3)

Step-by-step explanation:

1. First figure

We plot the parabola as given in the attached diagram.

As it is facing upwards, the equation goes as x² = 4py

where, p = 4 (refer the attached diagram)

x² = 4py

x² = 4 (4) y

∴, standard form of parabola is x² = 16 y

2. Second figure

(y + 3)² = 4 (x - 1)

Comparing the given equation with the standard form

(y - k)² = 4p (x - h)

Now from this equation we get to know that

h = 1

p = 1

Directrix is x = (h - p)

So, x = 0

3. Third figure

3x² + 24x - 2y + 52 = 0

3x² + 24x = 2y - 52

3 (x² + 8x) = 2 (y - 26)

(x² + 8x) = 2 (y - 26) / 3

Adding 16 on both sides,

x² + 8x + 16 = 2 (y - 26) / 3 + 16

(x + 4)² = 2/3 y - 52/3 + 16

(x + 4)² = 2/3 y - 4/3

(x + 4)² = 2/3 (y - 2)

4. Fourth figure

(y + 1)² = 12 (x - 3)

Comparing the given equation with the standard form

(y - k)² = 4p (x - h)

Now from this equation we get to know that

k = -1

h = 3

p = 3

Gayle identifies that the vertex of the parabola is <u>(3, -1)</u> . The parabola opens <u>right</u>, and the focus is <u>3 </u>units away from the vertex. The directrix is <u>6 </u>units from the focus. The focus is the point <u>(6, -1)</u>. The directrix of the equation is <u>x = 0.</u>

5. Fifth figure

Focus = (2, 6)

Directrix is x = 4

Therefore, it follows the standard form

(y - k)² = 4p (x - h)

Directrix is given by x = h-p = 4

Focus is given by (h + p, k) = (2, 6)

Solving for (h - p) = 4, (h + p) = 2

2 - p - p = 4

-2p = 2

p = -1

Hence, h = 3

Therefore, the standard form can be written as

(y - 6)² = 4p (x - 3)

7 0
3 years ago
2 (4z-1)=3(z+2) simplify
Novosadov [1.4K]

Answer:

8/5

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
a pool in the shape of rectangle has a perimeter of 80 feet. The pool is 8 Feet less wide than its long. Find the length and wid
Aneli [31]
Hello!

To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w

To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.

2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24

Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.

Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.

As our final answer, the width of the pool is 16 feet, and the length is 24 feet.

Hope this helps!

5 0
3 years ago
A company is designing a new cylindrical water bottle. The volume of the bottle will be 211 cm^3. The height of the water bottle
Zinaida [17]

Answer:

The correct answer is 2.912 cm.

Step-by-step explanation:

A company is designing a new cylindrical water bottle.

Volume of a cylinder is given by π × r^{2} × h, where h is the height of the cylinder and r is the radius of the cylinder.

The volume of each bottle will be 211 cm^{3}.

The height (h) of the water bottle be 7.9 cm.

Let the radius of the bottle be r cm.

∴ π × r^{2} × h = 211 ; (π = 3.15)

⇒ r^{2} × 24.885 = 211

⇒ r = 2.912

The radius of the water bottle is 2.912 cm.

4 0
3 years ago
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