Answer:
D. Minimum at (3, 7)
Step-by-step explanation:
We can add and subtract the square of half the x-coefficient:
y = x^2 -6x +(-6/2)^2 +16 -(-6/2)^2
y = (x -3)^2 +7 . . . . . simplify to vertex form
Comparing this to the vertex for for vertex (h, k) ...
y = (x -h)^2 +k
We find the vertex to be ...
(3, 7) . . . . vertex
The coefficient of x^2 is positive (+1), so the parabola opens upward and the vertex is a minimum.
<span>A 15° sector in a circle has an area of 11.9 m2. What is the area of the circle?
The area of the circle will be found as follows:
the fraction of the sector=15/360=1/24
the area of the circle will be:
area=(fraction of the circle)/(fraction of the sector)*(area of the sector)
=1/(1/24)</span>×11.9
=285.6 m²
Vertex is (-3 , 21 ) you can put <span>y=-2x^2-12x+3 in google and you will see the function</span>
Answer: i think it’s C
Step-by-step explanation:
Applying implicit differentiation, it is found that dy/dt when y=π/4 is of:
a-) -√2 / 2.
<h3>What is implicit differentiation?</h3>
Implicit differentiation is when we find the derivative of a function relative to a variable that is not in the definition of the function.
In this problem, the function is:
xcos(y) = 2.
The derivative is relative to t, applying the product rule, as follows:


Since dx/dt=−2, we have that:

When y = π/4, x is given by:
xcos(y) = 2.

Hence:


Since cot(pi/4) = 1, we have that:

Which means that option a is correct.
More can be learned about implicit differentiation at brainly.com/question/25608353
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