<span>(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.
cos 49 = ground / plank
cos 49 = 3 / plank
plank = cos 49 / 3
plank = 0.10 ft
</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
</span><span>
The remaining angle is equal to
angle = 180 - (90+49)
angle = 41
Finding the height.
tan 41 = height / ground
tan 41 = height / 3
height = tan 41 / 3
height = 0.05 ft.
(A) 0.10 feet
(B) 0.05 feet</span>
The equation is Oy = 3/6x
Answer:
90cm cube
Step-by-step explanation:
V= lbh
V= 6×3×5
V= 90cm cube
Let the Length be L and the Width be W
The area is 8 cm²
LW = 8
The perimeter is 12
2(L + W) = 12
L + W = 6
Solve L and W:
LW = 8 --------------- (1)
L + W = 6------------ (2)
Equation (2):
L + W = 6
L = 6 - W -------------- Sub into (1)
(6 - W) W = 8
6W - W² = 8
W² - 6W + 8 =0
(W -2 )(W - 4) = 0
W = 2 or 4
When W =2, L = 6 - 2 = 4
When W = 4, L = 6 - 4 = 2
Answer: The Width is 2 cm and the Length is 4 cm
Answer:
72
Step-by-step explanation: