Help please !!! I don’t know what to do

Mathematics

1 answer:

Hatshy [7]3 years ago

3 0

9514 1404 393

Answer:

6. x = 3

8. x = -7.5

Step-by-step explanation:

Put the number in place of the expression it is equal to, then solve for x.

6) g(x) = -x +5

2 = -x +5 . . . . . . . . . g(x) is replaced by 2, because g(x) = 2

x +2 = 5 . . . . . . . . . . add x to both sides

x = 3 . . . . . . . . . . . . . subtract 2 from both sides

8) n(x) = -2x -21

-6 = -2x -21 . . . . . n(x) is replaced by its equal: -6

3 = x +10.5 . . . . . . divide both sides by -2

-7.5 = x . . . . . . . . . subtract 10.5 from both sides

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<em>Additional comment</em>

We have shown a couple of ways these equations can be solved. You can separate the x-term and the constant terms before you divide by the x-coefficient, or you can do it after. In the first equation, we could have solved it ...

2 -x +5

-3 = -x . . . . subtract 5

3 = x . . . . . . multiply by -1

The way we did it avoids negative numbers.

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Yuri [45]

Answer:

$15\frac{d^{2}y(t)}{dt^{2} } - 441.45y(t) =$ ± $170 cos(5t)$

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Step-by-step explanation:

See the attached image

This problem involves Newton's 2nd Law which is: ∑F = ma, we have that the acting forces on the mass-spring system are: $F_{r} (t)$ that correspond to the force of resistance on the mass by the action of the spring and $F(t)$ that is an external force with unknown direction (that does not specify in the enounce).

For determinate $F_{r} (t)$ we can use Hooke's Law given by the formula $F_{r} (t) = k y(t)$ where $k$ correspond to the elastic constant of the spring and $y(t)$ correspond to the relative displacement of the mass-spring system with respect of his rest state.