<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
8 / sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan A = BC / AC
tan 30 = BC / 8
8 tan 30 = BC
8 * sqrt(3)/3 = BC
8/3 sqrt(3) = BC
Answer:
google
Step-by-step explanation:
dgodsl,fdrgefsdfvr34ewf
Answer:
9x+1
Step-by-step explanation:
combine 2x+7x then add the 1