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Greeley [361]
3 years ago
7

Can some explain how to do this?

Mathematics
1 answer:
zepelin [54]3 years ago
4 0

Answer:

  • Exact Area = 210.25pi - 210
  • Approximate Area = 450.185

The units for the area are in square inches or in^2. The approximate value shown above is when using pi = 3.14

=============================================================

Explanation:

Use the pythagorean theorem to find the length of the hypotenuse

  • a = 20
  • b = 21
  • c = unknown

a^2 + b^2 = c^2

20^2 + 21^2 = c^2

400 + 441 = c^2

c^2 = 841

c = sqrt(841)

c = 29

The hypotenuse is 29 inches long. This is the diameter of the circle. Half of that is the radius at r = d/2 = 29/2 = 14.5 inches.

The area of the circle is...

A = pi*r^2

A = pi*(14.5)^2

A = pi*210.25

A = 210.25pi

Which is exact in terms of pi

We'll subtract off the triangular region as this isn't shaded in. The area of the triangle is base*height/2 = 20*21/2 = 420/2 = 210 square inches.

So the shaded region is therefore 210.25pi - 210 square inches

This approximates to 210.25*3.14 - 210 = 450.185 when using the approximation pi = 3.14; use more decimal digits of pi to get a more accurate value.

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The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
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Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

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Answer:

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Step-by-step explanation:

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<u>Find the sides using distance formula:</u>

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