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2 years ago

Can you please Solve for x?

Mathematics

1 answer:

GaryK [48]2 years ago

3 0

tan( 31 ) = x / 39

0.600860619 = x / 39

x = 0.600860619 × 39

x = 23.433564141

______________________________

Round to the nearest tenth :

x = 23.4

Round to the nearest hundredth :

x = 23.43

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The mean useful life of xar batteries is 48 months. They have a standard deviation of 5

andre [41]

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3 0

1 year ago

One side of a triangle is increasing at a rate of 9 cm/s and a second side is decreasing at a rate of 2 cm/s. if the area of the

LenKa [72]

Use the attached figure to guide yourself through the explanation. In the figure:
$a=21cm, b=36cm, \widehat{C}=\frac{\pi}{6}$ .
We know that:
$\frac{da}{dt}=9,\frac{db}{dt}=-2$
Also remmeber that the area of a triangle is:
$A=\frac{Base\times Height}{2}$
The hegiht is shown in the figure in red, the base is just the b side.
Using the angle C the area of the triangle is:
$A=\frac{1}{2}ab\cos(\widehat{C})\implies2A=ab\cos(\widehat{C})$
Now taking the derivative of the area 2A with respect to t we have:
$2\frac{dA}{dt}=b\cos(\widehat{C})\frac{da}{dt}+a\cos(\widehat{C})\frac{db}{dt}-ab\sin(\widehat{C})\frac{d\widehat{C}}{dt}$

Replacing with the right values:
$\frac{dA}{dt}=0\\
\\
\cos({\widehat{C}})=\frac{\sqrt{3}}{2}\\ \\
\sin({\widehat{C}})=\frac{1}{2}\\ \\

$
yields:
$0=36\frac{\sqrt{3}}{2}.9-21\frac{\sqrt{3}}{2}.2-\frac{1}{2}.21.36.\frac{d\widehat{C}}{dt}\implies \frac{d\widehat{C}}{dt}=\frac{141}{378}\sqrt{3}$

5 0

3 years ago

The production department has installed a new spray machine to paint automobile doors. As is common with most spray guns, unsigh

Nesterboy [21]

Answer:

The numbers of doors that will have no blemishes will be about 6065 doors

Step-by-step explanation:

Let the number of counts by the worker of each blemishes on the door be (X)

The distribution of blemishes followed the Poisson distribution with parameter $\lambda =0.5$ / door

The probability mass function on of a poisson distribution Is:

$P(X=x) = \dfrac{e^{- \lambda } \lambda ^x}{x!}$

$P(X=x) = \dfrac{e^{- \ 0.5 }( 0.5)^ x}{x!}$

The probability that no blemishes occur is :

$P(X=0) = \dfrac{e^{- \ 0.5 }( 0.5)^ 0}{0!}$

$P(X=0) = 0.60653$

P(X=0) = 0.6065

Assume the number of paints on the door by q = 10000

Hence; the number of doors that have no blemishes is = qp

=10,000(0.6065)

= 6065

3 0

3 years ago

I need help solving this

shepuryov [24]

3x + 4 (27 - x ) = 89
3x +108 - 4x =89
x= 19(3 credits courses)
y = 89 -19 = 70
y = 70 (4 credit courses)
I hope this helps!

8 0

3 years ago

Solve on the interval [0,2pi)<br> (sinx-1)(2sin^2 x-5sinx+2)

BabaBlast [244]

Sin x - 1 = 0
sin x = 1
x 1 = π / 2
2 sin² x + 5 sin x + 2 = 0
Substitution: u = sin x
2 u² - 5 u + 2 = 0
2 u² - 4 u - u + 2 = 0
2 u ( u - 2 ) - ( u - 2 ) = 0
( u - 2 ) ( 2 u - 1 ) = 0
( sin x - 2 ) ( 2 sin x - 1 ) = 0
sin x - 2 = 0
sin x = 2 ( does not have solution )
2 sin x - 1 = 0
2 sin x = 1
sin x = 1/2
x 2 = π / 6 , x 3 = 5 π / 6
Answer:
x = π / 6 , π / 2 and 5 π / 6.

6 0

3 years ago